我有這個功能，我試圖向下滾動頁面并單擊鏈接。我已將代碼放入 for 循環中，因為我想打開多個選項卡。我試圖單擊的鏈接不在窗口視圖中，它們位于所有網頁通用的頁腳中。我的方法應該向下滾動，直到要單擊的鏈接可見，然后按住 Control 鍵并單擊并打開一個新選項卡。該方法在 Chrome 和 Internet Explorer 瀏覽器中運行良好，但在 Firefox 中失敗，提示要單擊的鏈接不存在。我認為盡管我放置了向下滾動的代碼，但它并沒有向下滾動。請幫忙。public static void checkHrefsWithBrowserUrls(List<WebElement> links) { String parentTab = null; String clickOnLink = Keys.chord(Keys.CONTROL, Keys.ENTER); log.debug("Checking that the links open the correct url"); for (WebElement link : links) { ((JavascriptExecutor)driver) .executeScript("arguments[0].scrollIntoView(true);", link); String href = link.getAttribute("href"); link.sendKeys(clickOnLink); WaitUtilities.sleep(1L); Iterator<String> handleIterator = driver.getWindowHandles().iterator(); parentTab = handleIterator.next(); if(handleIterator.hasNext()) { driver.switchTo().window(handleIterator.next()); WaitUtilities.waitForUrlToBe(url()); if(!href.equals(url())) { log.error("Link(s) opening wrong URL(s): " + url()); } driver.close(); driver.switchTo().window(parentTab); } } driver.switchTo().window(parentTab);}
1 回答
牛魔王的故事
TA貢獻1830條經驗 獲得超3個贊
這是處理狀態元素問題的偽代碼。
public static void checkHrefsWithBrowserUrls(String xpath)
{
String parentTab = null;
String clickOnLink = Keys.chord(Keys.CONTROL, Keys.ENTER);
log.debug("Checking that the links open the correct url");
int linksCount = driver.findElements(By.xpath(xpath)).size();
for (int linkCounter=1; linkCounter=linksCount, linkCounter++) {
link = driver.findElements(By.xpath(xpath)).get(linkCounter)
((JavascriptExecutor)driver)
.executeScript("arguments[0].scrollIntoView(true);", link);
String href = link.getAttribute("href");
link.sendKeys(clickOnLink);
WaitUtilities.sleep(1L);
Iterator<String> handleIterator = driver.getWindowHandles().iterator();
parentTab = handleIterator.next();
if(handleIterator.hasNext()) {
driver.switchTo().window(handleIterator.next());
WaitUtilities.waitForUrlToBe(url());
if(!href.equals(url())) {
log.error("Link(s) opening wrong URL(s): " + url());
}
driver.close();
driver.switchTo().window(parentTab);
}
}
driver.switchTo().window(parentTab);
}
添加回答
舉報
0/150
提交
取消