我想打印包含最大元音數的單詞。但問題是包含最大數量的句子的最后一個單詞沒有打印。請幫我解決這個問題。我的代碼如下。當我輸入輸入時'Happy New Year'，輸出是 'Yea'。但我想要輸出是'Year'import java.util.Scanner;public class Abcd { public static void main(String args[]) { Scanner sc = new Scanner(System.in); System.out.print("Enter The Word : "); String sentence = sc.nextLine(); String word = ""; String wordMostVowel = ""; int temp = 0; int vowelCount = 0; char ch; for (int i = 0; i < sentence.length(); i++) { ch = sentence.charAt(i); if (ch != ' ' && i != (sentence.length() - 1)) { word += ch; ch = Character.toLowerCase(ch); if (ch == 'a' || ch == 'e' || ch == 'i' || ch == 'o' || ch == 'u') { vowelCount++; } } else { if (vowelCount > temp) { temp = vowelCount; wordMostVowel = word; } word = ""; vowelCount = 0; } } System.out.println("The word with the most vowels (" + temp + ") is: " + " " + wordMostVowel); }}
1 回答
慕田峪9158850
TA貢獻1794條經驗 獲得超7個贊
您可以在空格處剪切單詞（正確），但也可以在最后一個字符處剪切，即使它不是空格（因此永遠不會處理該字符）。這是不正確的。
這是一種可能性：
import java.util.Scanner;
public class Abcd {
public static void main(String args[]) {
Scanner sc = new Scanner(System.in);
System.out.print("Enter the sentence : ");
String sentence = sc.nextLine();
String wordMostVowels = "";
int maxVowelCount = 0;
for (String word : sentence.split(" ")) {
int vowelCount = 0;
for (char c : word.toLowerCase().toCharArray()) {
if (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u') {
vowelCount++;
}
}
if (vowelCount > maxVowelCount) {
maxVowelCount = vowelCount;
wordMostVowels = word;
}
}
System.out.println("The word with the most vowels (" + maxVowelCount + ") is: " + wordMostVowels);
}
}
添加回答
舉報
0/150
提交
取消