我堆疊了 bs4 腳本，我需要獲取 href 鏈接或元內容，我該怎么做？基本上我需要得到這個：<meta itemprop="image" content="https://resources.reed.co.uk/profileimages/logos/thumbs/Logo_71709.png?v=20200828172950">或者<img src="https://resources.reed.co.uk/profileimages/logos/thumbs/Logo_71709.png?v=20200828172950" alt="Posted by Publica Group " width="120" height="50" class=" b-loaded" style="display: inline;">我嘗試這樣做： logoscrap = soup.find('meta', attrs={'itemprop': 'image'})和 logoscrap = soup.find('img', class_="b-loaded").attrs['src']但我的代碼不起作用...
1 回答
叮當貓咪
TA貢獻1776條經驗 獲得超12個贊
soup.find 返回 dict 對象，您可以直接從 dict 訪問屬性
img = soup.find('meta', attrs={'itemprop': 'image'})
logoscrap = img['content']
#output:
https://resources.reed.co.uk/profileimages/logos/thumbs/Logo_71709.png?v=20200828172950
或者
img = soup.find('img', class_="b-loaded")
logoscrap = img['src']
#output:
https://resources.reed.co.uk/profileimages/logos/thumbs/Logo_71709.png?v=20200828172950
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