我正在從數據庫中選擇值并將它們添加到循環中的數組中foreach，這是有效的。之后，我在第二個查詢中選擇其他值，我想將這些值添加到同一個數組中，如何實現這一點？請注意，我還不擔心代碼的安全性。我的（簡化的）代碼如下；$users_arr = array();// first query$db->setQuery("SELECT id, name, username, email FROM sometable WHERE name = '$name' ");$results = $db->loadObjectList();foreach ($results as $result) { $userid = $result->id; $name = $result->name; $username = $result->username; $email= $result->email; $users_arr[] = array( "id" => $userid, "name" => $name, "username" => $username, "email" => $email);}// second query$db->setQuery("SELECT status AS wb_status FROM anothertable ");$wb = $db->loadObject();$wb_status = $wb->wb_status;// add to original array $users_arr[] = array("wb_status" => $wb_status);echo json_encode($users_arr);exit();這會產生；[ { "id": "981", "name": "jo", "username": "jo123", "email": "[email protected]" }, { "wb_status": "Complete" }]我需要這種格式；[ { "id": "981", "name": "jo", "username": "jo123", "email": "[email protected]", "wb_status": "Complete" }]
1 回答
海綿寶寶撒
TA貢獻1809條經驗 獲得超8個贊
在第一個查詢之前運行第二個查詢并將元素添加到數組中foreach：
// second query becomes first
$db->setQuery("SELECT status AS wb_status FROM anothertable ");
$wb = $db->loadObject();
$wb_status = $wb->wb_status;
$users_arr = array();
// first query becomes second
$db->setQuery("SELECT id, name, username, email FROM sometable WHERE name = '$name' ");
$results = $db->loadObjectList();
foreach ($results as $result) {
$userid = $result->id;
$name = $result->name;
$username = $result->username;
$email= $result->email;
$users_arr[] = array(
"id" => $userid,
"name" => $name,
"username" => $username,
"email" => $email
"wb_status" => $wb_status, // Here
);
}
echo json_encode($users_arr);
exit();
更新：另一種方法是迭代$users_arr并向每個元素插入所需的數據：
// ...
$db->setQuery("SELECT status AS wb_status FROM anothertable ");
$wb = $db->loadObject();
$wb_status = $wb->wb_status;
// I use `&` here so as to pass `$item` as a
// reference to original item in `$users_arr`
foreach ($users_arr as &$item) {
$item["wb_status"] = $wb_status;
}
echo json_encode($users_arr);
exit();
- 1 回答
- 0 關注
- 185 瀏覽
添加回答
舉報
0/150
提交
取消