我必須使用 轉換字符串preg_replace。下面是我需要轉換的字符串@[ Test Career 12](career:235)@[ Testing11](business:2)@[ Username](user:1)some text我已經創建了代碼來替換內容，但它不起作用。請檢查下面的代碼，$Rtm = '@[ Test Career 12](career:235)@[ Testing11](business:2)@[ Username](user:1)some text';if (preg_match("/@\[(.*?)\]\(user:(.*?)\)/", $Rtm, $match)) { $Rtm0 = preg_replace("/@\[(.*?)\]\(user:(.*?)\)/", '<a href="/en/main/profile_page_link/$2">$1</a>, ', $Rtm); $Rtm = rtrim($Rtm0, ', ');}if (preg_match("/@\[(.*?)\]\(business:(.*?)\)/", $Rtm, $match)) { $slug = "1"; $Rtm01 = preg_replace("/@\[(.*?)\]\(business:(.*?)\)/", '<a href="/en/business/' . $slug . '/about">$1</a>, ', $Rtm); $Rtm = rtrim($Rtm01, ', ');}if (preg_match("/@\[(.*?)\]\(career:(.*?)\)/", $Rtm, $match)) { $slug = "2"; $Rtm02 = preg_replace("/@\[(.*?)\]\(career:(.*?)\)/", '<a href="/en/main/' . $slug . '/about">$1</a>, ', $Rtm); $Rtm = rtrim($Rtm02, ', ');}echo $Rtm;上述代碼的輸出是，<a href="/en/main/profile_page_link/1"> Test Career 12](career:235)</a><a href="/en/business/1/about"> Testing11</a>, @[ Username, some text但我需要的輸出是，<a href="/en/main/2/about"> Test Career 12</a>, <a href="/en/business/1/about"> Testing11</a>, <a href="/en/main/profile_page_link/1"> Username</a> some text給定的字符串只是一個演示，順序可能會改變，因為它是動態的。但結構是一樣的。如何獲得所需的輸出。我的編碼有問題嗎。
2 回答
墨色風雨
TA貢獻1853條經驗 獲得超6個贊
為此，我將preg_replace_callback捕獲 中的文本[]、slug 類型（user、career或business）和值（對于 slug?user）分組，并將它們傳遞到回調以形成 URL：
$Rtm = '@[ Test Career 12](career:235)@[ Testing11](business:2)@[ Username](user:1)some text';
$Rtm = preg_replace_callback('/@\[([^]]*)\]\(([a-z]+):([^)]*)\)/', function ($match) {
? ? switch($match[2]) {
? ? ? ? case 'user':
? ? ? ? ? ? return "<a href=\"/en/main/profile_page_link/$match[3]\">$match[1]</a>";
? ? ? ? ? ? break;
? ? ? ? case 'business':
? ? ? ? ? ? return "<a href=\"/en/business/1/about\">$match[1]</a>";
? ? ? ? ? ? break;
? ? ? ? case 'career':
? ? ? ? ? ? return "<a href=\"/en/main/2/about\">$match[1]</a>";
? ? ? ? ? ? break;
? ? ? ? default:
? ? ? ? ? ? return "";
? ? ? ? ? ? break;
? ? }
}, $Rtm);
echo $Rtm;
輸出（對于您的輸入字符串）：
<a href="/en/main/2/about"> Test Career 12</a><a href="/en/business/1/about"> Testing11</a><a href="/en/main/profile_page_link/1"> Username</a>some text
BIG陽
TA貢獻1859條經驗 獲得超6個贊
使用@\[([^][]*?)\]而不是@\[(.*?)\] 演示和解釋。
rtrim所有更換后僅執行一次。
$Rtm = '@[ Test Career 12](career:235)@[ Testing11](business:2)@[ Username](user:1)some text';
if (preg_match("/@\[([^][]*?)\]\(user:(.*?)\)/", $Rtm, $match)) {
$Rtm = preg_replace("/@\[([^][]*?)\]\(user:(.*?)\)/", '<a href="/en/main/profile_page_link/$2">$1</a>, ', $Rtm);
}
if (preg_match("/@\[([^][]*?)\]\(business:(.*?)\)/", $Rtm, $match)) {
$Rtm = preg_replace("/@\[([^][]*?)\]\(business:(.*?)\)/", '<a href="/en/business/$2/about">$1</a>, ', $Rtm);
}
if (preg_match("/@\[([^][]*?)\]\(career:(.*?)\)/", $Rtm, $match)) {
$Rtm = preg_replace("/@\[([^][]*?)\]\(career:(.*?)\)/", '<a href="/en/main/$2/about">$1</a>, ', $Rtm);
}
$Rtm = rtrim($Rtm, ', ');
echo $Rtm;
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