從 Location 擴展的類 AddressLocation 和 AirportLocation。當 json 中的“type”字段作為“ADDRESS”或“AIRPORT”出現時，jackson 正確地將其分別反序列化為 AddressLocation 和 AirportLocation 類。當“type”不存在時，jackson 不知道如何反序列化該對象。有沒有一種方法可以配置杰克遜，如果“類型”不存在或為空，則使用默認類型作為“地址”？//從以下內容中刪除了 getters、setters 和構造函數@JsonInclude(value= JsonInclude.Include.NON_EMPTY)@JsonIgnoreProperties(ignoreUnknown = true)@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY, property = "type", visible=false)@JsonSubTypes({         @JsonSubTypes.Type(value = AirportLocation.class, name = "AIRPORT"),        @JsonSubTypes.Type(value = AddressLocation.class, name = "ADDRESS")})public abstract class Location {    private List<Float> geoCoordinates;    private String city;    private String countryCode;  }public class AddressLocation extends Location {    private String province;    private String postalCode;    private String streetAddress;    public AddressLocation(final List<Float> geoCoordinates, final String city, final String countryCode,                           final String province,                           final String postalCode, final String streetAddress) {        super(geoCoordinates, city, countryCode);        this.province = province;        this.postalCode = postalCode;        this.streetAddress = streetAddress;    }}public class AirportLocation extends Location { String airportCode;}我得到的錯誤是 -Missing type id when trying to resolve subtype of [simple type, class ***]: missing type id property 'type' at [Source: (String)"{"geo_coordinates":[1.17549435E-38],"city":"Whateverville","country_code":"WW"}"; line: 1, column: 79]