在 python 課程中解決這個問題，但我終生無法弄清楚為什么這行不通。我寧愿它給我一個錯誤也不愿打印 0！問題給了我顯示的字符串的變量x，需要打印第一次y使用的索引。x = 'Poisson geometry plays an important role in noncommutative geometry.'y = 'u'i = 0while i == 0: for o in x: if o == y: print(y, "is first seen in index = ", y.index(o)) i += 1顯示的代碼返回：u is first seen in index = 0
3 回答
心有法竹
TA貢獻1866條經驗 獲得超5個贊
你想要索引x嗎？在這種情況下，使用x.index(o)where 搜索oin x。
x = 'Poisson geometry plays an important role in noncommutative geometry.'
y = 'u'
i = 0
while i == 0:
for o in x:
if o == y:
print(y, "is first seen in index = ", x.index(o))
i += 1
然而，正確的寫法是沒有循環：
x = 'Poisson geometry plays an important role in noncommutative geometry.'
y = 'u'
print(y, "is first seen in index = ", x.index(y))
輸出：
u is first seen in index = 51
FFIVE
TA貢獻1797條經驗 獲得超6個贊
你需要迭代嗎？如果您保留前 2 行然后使用，您將在不使用,或 的情況下x.index(y)獲得相同的結果。whileforif
x = 'Poisson geometry plays an important role in noncommutative geometry.'
y = 'u'
print(y, "is first seen in index = ", x.index(y))
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