我有下一個 GORM 模型package entityimport (    "github.com/jinzhu/gorm")type InterfaceEntity interface {}type User struct {    InterfaceEntity    gorm.Model    Name string}我嘗試將 GORM 實體類型傳遞到基礎 crud 存儲庫中。我的基礎 crud 存儲庫：package repositoryimport (    "billingo/model/entity"    "fmt"    "github.com/jinzhu/gorm"    "reflect")type CrudRepository struct {    *BaseRepository}func NewCrudRepository(db *gorm.DB) CrudRepositoryInterface {    repo := NewBaseRepository(db).(*BaseRepository)    return &CrudRepository{repo}}func (c CrudRepository) Find(id uint, item entity.InterfaceEntity) entity.InterfaceEntity {    fmt.Println("--- Initial")    var local entity.User    fmt.Println("--- local: ", reflect.TypeOf(local), local)    fmt.Println("--- Item:  ", reflect.TypeOf(item), item)    fmt.Println("--- Values")    c.db.First(&local, id)    fmt.Println("--- local: ", reflect.TypeOf(local), local)    c.db.First(&item, id)    fmt.Println("--- Item: ", reflect.TypeOf(item), item)    return item}正如您在這里看到的，方法中有item和local變量Find()。我item通過服務的下一種方式傳遞：func (c CrudService) GetItem(id uint) entity.InterfaceEntity {    var item entity.User    return c.repository.Find(id, item)}看來whatlocal和item必須是equals和behavior必須是等價的。但是輸出是--- Initial--- local:  entity.User {<nil> {0 0001-01-01 00:00:00 +0000 UTC 0001-01-01 00:00:00 +0000 UTC <nil>} }--- Item:   entity.User {<nil> {0 0001-01-01 00:00:00 +0000 UTC 0001-01-01 00:00:00 +0000 UTC <nil>} }--- Values--- local:  entity.User {<nil> {1 0001-01-01 00:00:00 +0000 UTC 0001-01-01 00:00:00 +0000 UTC <nil>} test 1}--- Item:  entity.User {<nil> {0 0001-01-01 00:00:00 +0000 UTC 0001-01-01 00:00:00 +0000 UTC <nil>} }INFO[0000] User info                                     user="{<nil> {0 0001-01-01 00:00:00 +0000 UTC 0001-01-01 00:00:00 +0000 UTC <nil>} }" user-id=1(/home/mnv/go/src/billingo/model/repository/CrudRepository.go:29) [2019-05-17 17:07:37]  unsupported destination, should be slice or struct item從服務傳遞到消息不支持的目標，應該是 slice 或 struct如何item正確通過，我需要像 with 這樣的行為local？