首頁猿問基于另外兩個對象數組創建對象數組

基于另外兩個對象數組創建對象數組

JavaScript

慕標琳琳 2023-06-15 15:45:20

我有兩個對象數組，我想基于它們創建第三個對象并添加一些新的鍵/值?；A數據const oldArray = [{id: 1, name: 'Test', age: 25, skill: 120},?{id: 2, name: 'Test25', age: 10, skill: 120}];修改后的數據const newArray = [{id: 1, name: 'Test2', age: 50, skill: 200},{id: 2, name: 'Test25', age: 25, skill: 120}];我想收到類似的東西：const expectedResultArray = [? {id: 1, oldName: 'Test', newName: 'Test2', oldAge: 25, newAge: 50, ageDifference: 25, oldSkill: 120, newSkill: 200, skillDifference: 80 },? {id: 2, oldName: 'Test25', newName:'Test25', oldAge: 10, newAge: 25, ageDifference: 15, oldSkill:120, newSkill: 120, skillDefference: 0}]如您所見，預期數組是基于兩個數組的舊計算和全新計算的組合。我怎樣才能做到這一點？我試過reduce()但是我被困在嘗試中：var createNewArray = (...objects) =>?? Object.values(objects.reduce((a, e) => {? ? a[e.id] = a[e.id] || {id: e.id};? // struggling to proceed here?? ? return a;? }, {}));console.log(createNewArr(...oldArray, ...newArray));

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2 回答

陪伴而非守候

TA貢獻1757條經驗獲得超8個贊

如果對象的順序相同，那么您可以試試這個。否則我們需要根據id.

const oldArray = [

{id: 1, name: 'Test', age: 25, skill: 120},

{id: 2, name: 'Test25', age: 10, skill: 120}];

const newArray = [

{id: 1, name: 'Test2', age: 50, skill: 200},

{id: 2, name: 'Test25', age: 25, skill: 120}];

const Result = newArray.map((item, i) => {

let oldConverted = renameObject(oldArray[i], 'old');

let newConverted = renameObject(item, 'new');

newConverted.ageDifference = newConverted.newAge - oldConverted.oldAge;

newConverted.skillDefference = newConverted.newSkill - oldConverted.oldSkill;

return Object.assign({}, newConverted, oldConverted);

});

function renameObject(obj, type) {

let newObj = {};

newObj.id = obj.id;

Object.keys(obj).forEach((key) => {

if (key != 'id') {

newObj[type + capitalize(key)] = obj[key];

}

});

return newObj;

}

function capitalize(string) {

return string.charAt(0).toUpperCase() + string.slice(1);

}

console.log(Result);

反對回復 2023-06-15

倚天杖

TA貢獻1828條經驗獲得超3個贊

好吧，解決方案比我預期的要容易......（Facepalm）

const oldArray = [{id: 1, name: 'Test', age: 25, skill: 120}, {id: 2, name: 'Test25', age: 10, skill: 120}];

const newArray = [{id: 1, name: 'Test2', age: 50, skill: 200}, {id: 2, name: 'Test25', age: 25, skill: 120}];

const generateNewArr = () => {

return oldArray.map((row,index) => {

return {

id: row.id,

oldName: row.name,

newName: newArray[index].name,

oldAge: row.age,

newAge: newArray[index].age,

ageDifference: newArray[index].age - row.age,

oldSkill: row.skill,

newSkill: newArray[index].skill,

skillDifference: newArray[index].skill - row.skill

}

})

}

console.log(generateNewArr())

反對回復 2023-06-15

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