我正在嘗試根據兩個字段 [ Name , Old name ] 按升序對對象列表進行排序，其中Name字段值可以是破折號（“-”），如果名稱是破折號，那么它將被添加到列表的末尾. [像下面的順序：名稱：舊名稱]SENSITIVE: COMP Operations: COMP OperationsSENSITIVE: Court procedural documents: Court procedural documentsSENSITIVE: Staff matter: Staff MatterSPECIAL HANDLING: ETS Critical: ETS Critical-: ETS Limited-: EU Satellite Navigation matters-: Limited ETS Joint Procurement到目前為止，我得到了以下結果：-: ETS Limited-: EU Satellite Navigation matters-: Limited ETS Joint ProcurementSENSITIVE: COMP Operations: COMP OperationsSENSITIVE: Court procedural documents: Court procedural documentsSENSITIVE: Staff matter: Staff MatterSPECIAL HANDLING: ETS Critical: ETS Critical領域模型：class Marking { String name; String oldName; public Marking(String name, String oldName) { this.name = name; this.oldName = oldName; } public String getName() { return name; } public void setName(String name) { this.name = name; } public String getOldName() { return oldName; } public void setOldName(String oldName) { this.oldName = oldName; } @Override public String toString() { return "Marking [name=" + name + ", oldName=" + oldName + "]"; }}和解決方案類：public class Solution { public static void main(String[] args) { List<Marking> markings = new ArrayList<>(); markings.add(new Marking("-", "Limited ETS Joint Procurement")); markings.add(new Marking("-", "EU Satellite Navigation matters")); markings.add(new Marking("SENSITIVE: Court procedural documents", "Court procedural documents")); markings.add(new Marking("SENSITIVE: COMP Operations", "COMP Operations")); markings.add(new Marking("-", "ETS Limited")); markings.add(new Marking("SENSITIVE: Staff matter", "Staff Matter")); markings.add(new Marking("SPECIAL HANDLING: ETS Critical", "ETS Critical"));任何人都可以給我一些建議，如何將破折號名稱對象添加到列表的末尾，其中舊名稱應按升序排列。
2 回答
吃雞游戲
TA貢獻1829條經驗 獲得超7個贊
這是我很快想到的一個選項：
Collections.sort(markings, (o1, o2) -> {
int value = o1.getName().compareToIgnoreCase(o2.getName());
if(value == 0) {
return o1.getOldName().compareToIgnoreCase(o2.getOldName());
}
if(o1.getName().equals("-")) {
return 1;
}
if(o2.getName().equals("-")) {
return -1;
}
return value;
});
縹緲止盈
TA貢獻2041條經驗 獲得超4個贊
這是一個建議。順序很好，我們所做的就是取出所有以“-”開頭的元素并將它們從列表中刪除，然后將它們添加回末尾。這是低效的，但它是一種決心。
public static void main(String[] args) {
List<Marking> markings = new ArrayList<>();
markings.add(new Marking("-", "Limited ETS Joint Procurement"));
markings.add(new Marking("-", "EU Satellite Navigation matters"));
markings.add(new Marking("SENSITIVE: Court procedural documents", "Court procedural documents"));
markings.add(new Marking("SENSITIVE: COMP Operations", "COMP Operations"));
markings.add(new Marking("-", "ETS Limited"));
markings.add(new Marking("SENSITIVE: Staff matter", "Staff Matter"));
markings.add(new Marking("SPECIAL HANDLING: ETS Critical", "ETS Critical"));
markings.sort((o1, o2) -> {
int value = o1.getName().compareToIgnoreCase(o2.getName());
if (value == 0) {
return o1.getOldName().compareToIgnoreCase(o2.getOldName());
}
return value;
});
List<Marking> dashed = markings.stream().filter(marking -> marking.name.startsWith("-") || marking.oldName.startsWith("-"))
.collect(Collectors.toList());
markings.removeAll(dashed);
markings.addAll(dashed);
for (Marking marking : markings) {
System.out.println(marking.getName() + ": " + marking.getOldName());
}
}
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