我寫了一個網絡抓取代碼，掃描工作門戶中的所有頁面，并在功能中報告滿足薪水要求的工作機會。對我來說重要的字段是職位、雇主、薪水和鏈接。我現在使用的是 getText() 方法，但需要所有元素。結果看起來像：Zubny lekár/lekárka DENTAL CARE Dr. Rosa, s. r. o.Námestie sv. Franti?ka, Karlova Ves        Od 4 500 EUR/mesiac    Pridané Pred 4 dňami  Prida? k vybranym   https://www.profesia.sk/praca/dental-care-dr-rosa/O3863429https://www.profesia.sk/praca/dental-care-dr-rosa/O3863429Head of Core Technology DevelopmentESET, spol. s r.o.Bratislava        4 500 EUR/mesiac    Pridané pred 2 ty?dňami  Prida? k vybranym   https://www.profesia.sk/praca/eset/C22141https://www.profesia.sk/praca/eset/O3933805https://www.profesia.sk/praca/eset/O3933805它需要兩個不必要的項目并復制鏈接（因為 <a 'href' 中有 2 到 3 個鏈接）有更好的主意嗎？def search4job(salary):    import bs4, requests, re    #Classes -> employer: class='employer'>    # -> salary ".label"    # -> Job Title class='title'    # -> TODO: link     base_url= 'https://www.profesia.sk/praca/bratislava/plny-uvazok/?languages=73&page_num={}'    page = 1 #to start from page1    request = requests.get(base_url.format(page)) #to take complete url    HTML = bs4.BeautifulSoup(request.text,'lxml')     pattern = r'(\d\s\d\d\d)' #salary pattern    while len(HTML.select(".list-row"))>0:         #in pages without job offer the len of list-row is 0, iterates until there are no job offers