有沒有辦法在 a 中執行以下操作html/template？{{template "mytemplate" struct{Foo1, Foo2 string}{"Bar1", "Bar2"}}}實際上在模板中，就像上面一樣。不是通過注冊的函數FuncMap返回結構。我試過了，但Parse很恐慌，請參閱 Playground。也許只是語法錯誤？
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拉丁的傳說
TA貢獻1789條經驗 獲得超8個贊
正如其他人所指出的，這是不可能的。模板在運行時解析，無需 Go 編譯器的幫助。因此，允許任意 Go 語法是不可行的（盡管請注意，這并非不可能，因為標準庫包含解析 Go 源文本的所有工具，請參閱標準庫中“前綴為”的包）go/。根據設計理念，復雜的邏輯應該在模板之外。
回到你的例子：
struct{Foo1,?Foo2?string}{"Bar1",?"Bar2"}這是一個結構復合文字，它在模板中不受支持，無論是在調用另一個模板時還是在其他地方。
使用自定義“參數”調用另一個模板具有以下語法（引用自text/template：Actions）：
{{template?"name"?pipeline}}
????The?template?with?the?specified?name?is?executed?with?dot?set
????to?the?value?of?the?pipeline.長話短說；博士；管道可能是一個常量，一個表示某個字段或方法的表達式（方法將被調用并使用其返回值），它可能是對某些“模板內置”函數的調用或自定義注冊函數或映射中的值。
管道在哪里：
管道可能是“命令”的鏈式序列。命令是一個簡單的值（參數）或一個函數或方法調用，可能帶有多個參數：
Argument ??The?result?is?the?value?of?evaluating?the?argument. .Method?[Argument...] ??The?method?can?be?alone?or?the?last?element?of?a?chain?but, ??unlike?methods?in?the?middle?of?a?chain,?it?can?take?arguments. ??The?result?is?the?value?of?calling?the?method?with?the ??arguments: ??????dot.Method(Argument1,?etc.) functionName?[Argument...] ??The?result?is?the?value?of?calling?the?function?associated ??with?the?name: ??????function(Argument1,?etc.) ??Functions?and?function?names?are?described?below.
一個論點是：
參數是一個簡單的值，由以下之一表示。
-?A?boolean,?string,?character,?integer,?floating-point,?imaginary ??or?complex?constant?in?Go?syntax.?These?behave?like?Go's?untyped ??constants.?Note?that,?as?in?Go,?whether?a?large?integer?constant ??overflows?when?assigned?or?passed?to?a?function?can?depend?on?whether ??the?host?machine's?ints?are?32?or?64?bits. -?The?keyword?nil,?representing?an?untyped?Go?nil. -?The?character?'.'?(period): ??. ??The?result?is?the?value?of?dot. -?A?variable?name,?which?is?a?(possibly?empty)?alphanumeric?string ??preceded?by?a?dollar?sign,?such?as ??$piOver2 ??or ??$ ??The?result?is?the?value?of?the?variable. ??Variables?are?described?below. -?The?name?of?a?field?of?the?data,?which?must?be?a?struct,?preceded ??by?a?period,?such?as ??.Field ??The?result?is?the?value?of?the?field.?Field?invocations?may?be ??chained: ????.Field1.Field2 ??Fields?can?also?be?evaluated?on?variables,?including?chaining: ????$x.Field1.Field2 -?The?name?of?a?key?of?the?data,?which?must?be?a?map,?preceded ??by?a?period,?such?as ??.Key ??The?result?is?the?map?element?value?indexed?by?the?key. ??Key?invocations?may?be?chained?and?combined?with?fields?to?any ??depth: ????.Field1.Key1.Field2.Key2 ??Although?the?key?must?be?an?alphanumeric?identifier,?unlike?with ??field?names?they?do?not?need?to?start?with?an?upper?case?letter. ??Keys?can?also?be?evaluated?on?variables,?including?chaining: ????$x.key1.key2 -?The?name?of?a?niladic?method?of?the?data,?preceded?by?a?period, ??such?as ??.Method ??The?result?is?the?value?of?invoking?the?method?with?dot?as?the ??receiver,?dot.Method().?Such?a?method?must?have?one?return?value?(of ??any?type)?or?two?return?values,?the?second?of?which?is?an?error. ??If?it?has?two?and?the?returned?error?is?non-nil,?execution?terminates ??and?an?error?is?returned?to?the?caller?as?the?value?of?Execute. ??Method?invocations?may?be?chained?and?combined?with?fields?and?keys ??to?any?depth: ????.Field1.Key1.Method1.Field2.Key2.Method2 ??Methods?can?also?be?evaluated?on?variables,?including?chaining: ????$x.Method1.Field -?The?name?of?a?niladic?function,?such?as ??fun ??The?result?is?the?value?of?invoking?the?function,?fun().?The?return ??types?and?values?behave?as?in?methods.?Functions?and?function ??names?are?described?below. -?A?parenthesized?instance?of?one?the?above,?for?grouping.?The?result ??may?be?accessed?by?a?field?or?map?key?invocation.??print?(.F1?arg1)?(.F2?arg2) ??(.StructValuedMethod?"arg").Field
正確的解決方案是注冊一個自定義函數，該函數構造要傳遞給模板調用的值，
另一個半解決方案可能是使用內置函數print或printf函數來連接您要傳遞的值，但這需要在另一個模板中拆分。
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