我有一個結構如下的對象?const data = [? ? { academicYearId: 1, classLevelId: 1, subjectId: 1, ...},? ? { academicYearId: 1, classLevelId: 1, subjectId: 2, ...},? ? { academicYearId: 1, classLevelId: 1, subjectId: 3, ...},? ? ,,,?]我需要創建一個將返回唯一列的函數,例如? ?const uniqueColumns = ( val, columns)=> {? ? ?//? ?}? ?const val = [? ? { id: 1, name: 'n1', val: 1 },? ? { id: 1, name: 'n1', val: 2 },? ? { id: 2, name: 'n2', val: 1 },? ? { id: 3, name: 'n2', val: 2 }? ?]? ?let result = uniqueColumns(val)? ?console.log(val)? ?/**?? ? * Expected? ? * [{ id: 1, name: 'n1'}, { id: 2, name: 'n2'}, { id: 3, name: 'n2'}]? ? */}我試圖查看如何從 JavaScript 中的對象數組中獲取不同的值?我已經設法想出了下面的? ?const uniqueColumns = (val, columns) =>?? ? ?([...new Set(? ? ? ?val.map(item =>?? ? ? ? ?columns.reduce((prev, next) =>?? ? ? ? ? ?({[next]: item[next], ...prev}), {})? ? ? ?).map(item => JSON.stringify(item)))? ? ?].map(item => JSON.parse(item)))? ?? ?const val = [? ? { id: 1, name: 'n1', val: 1 },? ? { id: 1, name: 'n1', val: 2 },? ? { id: 2, name: 'n2', val: 1 },? ? { id: 3, name: 'n2', val: 2 }? ?]? ?const result = uniqueColumns(val, ['id', 'name'])? ?console.log(result)我想問的是是否有更好的方法而不是必須將對象轉換為字符串然后再轉換回對象來實現這一點
如何從 Javascript 中的對象數組中獲取不同的對象
牛魔王的故事
2023-06-09 17:40:56