我試圖找出如何檢查二維數組是否連續包含 3 個相同的值。此二維數組將由用戶生成，因此用于檢查的函數必須是動態的。例如，假設用戶輸入 4x4。結果會是這樣  let arr=[    [" "," "," "," "],    [" "," "," "," "],    [" "," "," "," "],    [" "," "," "," "]  ]讓我向該數組添加一些值  let arr=[    [" "," ","x","x"],    ["x","x","x"," "],    [" "," "," "," "],    [" "," "," "," "]  ]我試圖用這個函數來解決這個問題，但昨天我注意到它不適合。  function checkArray(arr){    for(let i=0;i<arr.length;i++){      let count = 0;      for(let j=0;j<arr[i].length;j++){        if(arr[i][j] === 'x'){          count++;        }        if(count === 3 ){          console.log('x wins')        }      }    }  }    console.log(checkArray(arr)) //count will be 3 and console.logs 'x wins'.此時此刻，我認為一切正常，直到我嘗試像這樣填充數組。如您所見，沒有連續三個 X（我的意思是它們不是這樣的 - x,x,x），它們之間有一個空格。  let arr=[    [" "," ","x","x"],    ["x","x"," ","x"],    [" "," "," "," "],    [" "," "," "," "]  ]所以不應該滿足條件并且函數不應該是 console.log('w wins')。但確實如此。我解決這個問題的方法適用于整行，而不僅僅是連續 3 個 (x,x,x)。我希望我已經解釋清楚了。謝謝你的建議。