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如何循環遍歷 HTML 元素

如何循環遍歷 HTML 元素

滄海一幻覺 2023-06-09 10:53:57
此代碼使得當用戶單擊其中一種顏色 (color1-4) 時,它會設置display所有鞋子的 CSS 屬性,none但單擊的顏色除外,其display設置為block. 代碼看起來很臟,雇主不會批準。我將如何著手制作一個 for 循環,或者以其他方式使代碼更清晰?color2.addEventListener('click', () => {    shoe.style.display = "none";    shoe3.style.display = "none";    shoe5.style.display = "none";    shoe2.style.display = "block";    console.log('u removed it and added another');});color3.addEventListener('click', () => {    shoe.style.display = "none";    shoe3.style.display = "none";    shoe5.style.display = "none";    shoe2.style.display = "none";    shoe3.style.display = "block";    console.log('u removed it and added another');});color4.addEventListener('click', () => {    shoe.style.display = "none";    shoe3.style.display = "none";    shoe5.style.display = "none";    shoe3.style.display = "none";    shoe5.style.display = "block";    console.log('u removed it and added another');});color1.addEventListener('click', () => {    shoe.style.display = "block";    shoe2.style.display = "none";    shoe3.style.display = "none";    shoe4.style.display = "none";    shoe5.style.display = "none";    console.log('u removed it and added another');});color2.addEventListener('click', () => {    shoe.style.display = "none";    shoe3.style.display = "none";    shoe5.style.display = "none";    shoe2.style.display = "block";    console.log('u removed it and added another');});
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3 回答

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繁花不似錦

TA貢獻1851條經驗 獲得超4個贊

您需要使用 Array 和自定義函數來操作 DOM 元素,這是一個基本示例:


var shoes = [s1,s2,s3]; //DOM element arrays

colorShoe = (shoe) =>{

  for(let i=0; i<shoes.length;i++){

    if(shoes[i] === shoe){

      //Handling style

    }

}


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?
慕桂英546537

TA貢獻1848條經驗 獲得超10個贊

如果你不想使用 array ,你可以這樣做。只需使用 window['var name'+the index number] 然后你可以在后面添加你想做的事情 :D 謝謝 :D


color3.addEventListener('click', () => {

        for (var i = 1; i <= 5; i++) {

            if (i == 3) shoe.style.display = "block";

            else {

                window['shoe'+i].style.display = "none";

            }

        }

        console.log('u removed it and added another');

    });


    color4.addEventListener('click', () => {

        for (var i = 1; i <= 5; i++) {

            if (i == 4) shoe.style.display = "block";

            else {

                window['shoe'+i].style.display = "none";

            }

        }

        console.log('u removed it and added another');

    });


    color1.addEventListener('click', () => {

        for (var i = 1; i <= 5; i++) {

            if (i == 1) shoe.style.display = "block";

            else {

                window['shoe'+i].style.display = "none";

            }

        }

        console.log('u removed it and added another');

    });


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?
寶慕林4294392

TA貢獻2021條經驗 獲得超8個贊

請檢查一下,看看您是否可以像下面這樣修改您的代碼:


const colorList = [color1, color2, color3]; // you can add more

const shoeList = [shoe1, shoe2, shoe3]; // you can add more

[color1, color2, color3].forEach((color, colorIndex) => {

  color.addEventListener('click', () => {

    shoeList.forEach((shoe, shoeIndex) => {

      if (colorIndex === shoeIndex) {

        shoe.style.display = "block";

      } else {

        shoe.style.display = "none";

      }

    });

  });

});


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