嘗試從 2D 列表中刪除字符串，但僅在第一列中我的嘗試：list = [[x.strip('this') for x in y[0]] for y in list]示例列表：[["apple this","juice this"],
["orange this","lemonade this"],
["kiwi this","punch this"]]想要的結果：[["apple","juice this"],
["orange","lemonade this"],
["kiwi","punch this"]]只從第一列而不是第二列剝離“this”。最好甚至不檢查其他列。
4 回答
慕尼黑8549860
TA貢獻1818條經驗 獲得超11個贊
使用split()和zip()：
ee = [["apple this","juice this"],
["orange this","lemonade this"],
["kiwi this","punch this"]]
splitted = [x[0].split()[0] for x in ee] # ['apple', 'orange', 'kiwi']
later_lst = [x[1] for x in ee] # ['juice this', 'lemonade this', 'punch this']
print([list(l) for l in zip(splitted, later_lst)])
輸出：
[['apple', 'juice this'], ['orange', 'lemonade this'], ['kiwi', 'punch this']]
單線：
print([list(l) for l in zip([x[0].split()[0] for x in ee], [x[1] for x in ee])])
編輯：
較短的版本：
print([[x[0].split()[0], x[1]] for x in ee])
慕俠2389804
TA貢獻1719條經驗 獲得超6個贊
嘗試這個
list = [[(x if i else x.strip()) for i,x in enumerate(y)] for y in list]
POPMUISE
TA貢獻1765條經驗 獲得超5個贊
您可以使用
list = [[x.strip('strip this') if j==0 else x for j,x in enumerate(y)] for y in list]
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