如何打印文本文件，直到它與字符串匹配。考慮以下文本文件：00:d7:8f:0a:86:5c ST0123-AP22 Joined Flexconnect Manual No00:d7:8f:1e:d6:18 ST0123-AP14 Joined Flexconnect Manual No00:d7:8f:1e:dd:50 ST0123-AP03 Joined Flexconnect Manual NoEfficient AP Image Upgrade ..... EnabledGroup Radius/Local Auth Parameters : Radius Retransmit Count......................... 3 (default) Active Radius Timeout........................... 5 (default)Group Radius AP Settings:AP RADIUS server............ DisabledEAP-FAST Auth............... DisabledLEAP Auth................... DisabledEAP-TLS Auth................ DisabledEAP-TLS CERT Download....... DisabledPEAP Auth................... Disabled我想打印直到字符串“Efficient AP Image Upgrade ..... Enabled”的行：問題是行數因每個輸出而異。我也嘗試過 readlines 和 ttried for loop 但無法實現目標。
1 回答
九州編程
TA貢獻1785條經驗 獲得超4個贊
這應該工作：
with open('your_file.txt') as file:
for line in file:
if line == 'Efficient AP Image Upgrade ..... Enabled\n':
break
print(line)
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