TA貢獻1880條經驗 獲得超4個贊
使用正則表達式，您可以獲得第二個日期，如下所示：
const regex = /\/(?:.*?(\d{1,2}\w{3}\d{0,4}))\/.*?$/;
const [, date] = regex.exec("https://www.example.com/exampletitle21sep11oct2020/index.html");
console.log({ date })
const regex = /\/(?:.*?(\d{1,2}\w{3}\d{0,4}))\/.*?$/;
const [, date] = regex.exec("https://www.example.com/exampletitle21sep9oct2020/index.html");
console.log({ date });
console.log(regex.exec("https://www.example.com/exampletitle21sep9oct/index.html")[1])
TA貢獻1828條經驗 獲得超6個贊
您可以找到并解析包含以下模式的路徑：
^? ? ? ? ?Line start
.+? ? ? ? One or more of anything
(\d{2})? ?2-digit date
(\w{3})? ?3-letter month (lowercase)
(\d{2})? ?2-digit date
(\w{3})? ?3-letter month (lowercase)
(\d{4})? ?4-digit year
$? ? ? ? ?Line end
例子
我用moment來處理日期解析。
const expression = /^.+(\d{2})(\w{3})(\d{2})(\w{3})(\d{4})$/;
const format = 'DD MMM YYYY';
const toTitleCase = (str) => str.charAt(0).toUpperCase() + str.slice(1);
const parseDates = (path) => {
? const url? ? = new URL(path),
? ? ? ? tokens = url.pathname.split('/'),
? ? ? ? found? = tokens.find(token => token.match(expression));
? if (!found) return null;
? const [
? ? , startDate, startMonth, endDate, endMonth, year
? ] = found.match(expression);
? return {
? ? start : moment(`${startDate} ${toTitleCase(startMonth)} ${year}`, format),
? ? end? ?: moment(`${endDate} ${toTitleCase(endMonth)} ${year}`, format)
? };
};
const dates = parseDates('https://www.example.com/exampletitle21sep11oct2020/index.html');
console.log(dates);
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.29.1/moment.min.js"></script>
展開片段
TA貢獻1900條經驗 獲得超5個贊
僅使用一個正則表達式，一切都會簡單得多：
var url = 'https://www.example.com/exampletitle21sep11oct2020/index.html'
var res = url.match( /.*?(\d+[a-z]+\d{4})\/.*?$/i );
// res === [ "https://www.example.com/exampletitle21sep11oct2020/index.html", "11oct2020" ]
var endDate = res[1];
// endDate === "11oct2020"
或（但“exampletitle”不得以數字結尾）：
var res = url.match( /.*?(\d+[a-z]+)(\d+[a-z]+)(\d{4})\/.*?$/i );
// [ "https://www.example.com/exampletitle21sep11oct2020/index.html", "21sep", "11oct", "2020" ]
或者：
var res = url.match( /.*?(\d+)([a-z]+)(\d+)([a-z]+)(\d{4})\/.*?$/i );
// [ "https://www.example.com/exampletitle21sep11oct2020/index.html", "21", "sep", "11", "oct", "2020" ]
但是，如果您知道日期始終是 2 位數字（始終是“01”，而不是“1”），則“exampletitle”可以是任何字符串：
var res = url.match( /.*?(\d{2}[a-z]+\d{4})\/.*?$/i );
var res = url.match( /.*?(\d{2}[a-z]+)(\d+[a-z]+)(\d{4})\/.*?$/i );
var res = url.match( /.*?(\d{2})([a-z]+)(\d+)([a-z]+)(\d{4})\/.*?$/i );
TA貢獻1804條經驗 獲得超3個贊
試試這個更新
const url = "https://www.example.com/exampletitle21sep11oct2020/index.html";
const urlData = url.split('/');
const datePart = urlData[urlData.length-2];
const res = datePart.slice(-9); <-- this will give you "11oct2020" -->
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