我需要在給定 CIDR 和一些緩存地址的情況下開始生成 IP 地址。我在這里有一些代碼，我正在做字節。與存儲的地址進行比較，只選擇那些更大的。https://play.golang.org/p/yT_Mj4fR_jK這里出了什么問題？基本上我需要“62.76.47.12/28”中“62.76.47.9”的所有地址。在給定的 CIDR 范圍內生成 IP 是眾所周知的。謝謝。
3 回答
慕村9548890
TA貢獻1884條經驗 獲得超4個贊
此示例將打印從第一個地址 62.76.47.12/28 到 62.76.47.9 的地址。
游樂場： https: //play.golang.org/p/MUtbiKaQ_3-
package main
import (
"fmt"
"net"
)
func main() {
cidr := "62.76.47.12/28"
_, ipnet, _ := net.ParseCIDR(cidr)
ipFirst := ipnet.IP
ipFirstValue := toHost(ipFirst)
ipLast := net.ParseIP("62.76.47.9")
ipLastValue := toHost(ipLast)
fmt.Println("cidr: ", cidr)
fmt.Println("first: ", ipFirst)
fmt.Println("last: ", ipLast)
if ipLastValue < ipFirstValue {
fmt.Println("ugh")
return
}
for i := ipFirstValue; i < ipLastValue; i++ {
addr := toIP(i)
fmt.Println(addr)
}
}
func toHost(ip net.IP) uint32 {
i := ip.To4()
return uint32(i[0])<<24 + uint32(i[1])<<16 + uint32(i[2])<<8 + uint32(i[3])
}
func toIP(v uint32) net.IP {
v3 := byte(v & 0xFF)
v2 := byte((v >> 8) & 0xFF)
v1 := byte((v >> 16) & 0xFF)
v0 := byte((v >> 24) & 0xFF)
return net.IPv4(v0, v1, v2, v3)
}
富國滬深
TA貢獻1790條經驗 獲得超9個贊
如果你打印ìpMax，你會看到它的底層表示使用了 16 個字節。（另請參閱文檔
fmt.Printf("'%#v'\n",ipMax)
'net.IP{0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0xff, 0xff, 0x3e, 0x4c, 0x2f, 0x9}'
您可以轉換ipMax為 IPv4 表示以獲得所需的結果：
ipMax := net.ParseIP("62.76.47.9").To4()
皈依舞
TA貢獻1851條經驗 獲得超3個贊
使用IPAddress Go library，我可以提供兩種方法，一種方法類似于您通過迭代整個子網的建議，另一種方法是從給定地址開始并遞增直到達到最大地址。請注意，這些解決方案與 IPv6 的工作方式相同。免責聲明：我是項目經理。
62.76.47.12/28請注意，和 的封閉 CIDR 子網62.76.47.9/28是62.76.47.0/28，因此您實際上不需要同時提供62.76.47.12/28和62.76.47.9，您可以簡單地提供單個字符串62.76.47.9/28。但是為了堅持您提出的示例，我將使用這兩個字符串。
import (
? ? "fmt"
? ? "github.com/seancfoley/ipaddress-go/ipaddr"
)
func main() {
? ? cidrString, addrString := "62.76.47.12/28", "62.76.47.9"
? ? addr := ipaddr.NewIPAddressString(addrString).GetAddress()
? ? cidrAddr := ipaddr.NewIPAddressString(cidrString).GetAddress()
? ? iterateThroughSubnet(addr, cidrAddr) // solution 1
? ? incrementAddressToMax(addr, cidrAddr) // solution 2
}
func iterateThroughSubnet(addr, cidrAddr *ipaddr.IPAddress) {
? ? block := cidrAddr.ToPrefixBlock().WithoutPrefixLen()
? ? fmt.Printf("\nstarting with block %s, equivalent to %v,\nand address %s\n",
? ? ? ? cidrAddr.ToPrefixBlock(), block, addr)
? ? iterator := block.Iterator()
? ? for next := iterator.Next(); next != nil; next = iterator.Next() {
? ? ? ? fmt.Printf("compare %s with %s: %d\n", next, addr, next.Compare(addr))
? ? }
}
func incrementAddressToMax(addr, cidrAddr *ipaddr.IPAddress) {
? ? block := cidrAddr.ToPrefixBlock()
? ? max := block.GetUpper()
? ? fmt.Printf("\nstarting with block %s and address %s,\n"+
? ? ? ? "incrementing to block max %s\n", block, addr, max)
? ? for ; addr.Compare(max) <= 0; addr = addr.Increment(1) {
? ? ? ? fmt.Println(addr)
? ? }
}
輸出：
starting with block 62.76.47.0/28, equivalent to 62.76.47.0-15,
and address 62.76.47.9
compare 62.76.47.1 with 62.76.47.9: -1
compare 62.76.47.2 with 62.76.47.9: -1
compare 62.76.47.3 with 62.76.47.9: -1
compare 62.76.47.4 with 62.76.47.9: -1
compare 62.76.47.5 with 62.76.47.9: -1
compare 62.76.47.6 with 62.76.47.9: -1
compare 62.76.47.7 with 62.76.47.9: -1
compare 62.76.47.8 with 62.76.47.9: -1
compare 62.76.47.9 with 62.76.47.9: 0
compare 62.76.47.10 with 62.76.47.9: 1
compare 62.76.47.11 with 62.76.47.9: 1
compare 62.76.47.12 with 62.76.47.9: 1
compare 62.76.47.13 with 62.76.47.9: 1
compare 62.76.47.14 with 62.76.47.9: 1
compare 62.76.47.15 with 62.76.47.9: 1
starting with block 62.76.47.0/28 and address 62.76.47.9,
incrementing to block max 62.76.47.15/28
62.76.47.9
62.76.47.10
62.76.47.11
62.76.47.12
62.76.47.13
62.76.47.14
62.76.47.15
對于小子網，這兩種方法可能同樣有效，但是隨著子網變大，您希望避免第一個遞增遍歷整個子網的解決方案。如果需要，使用GetNetIp的方法ipaddr.IPAddress切換到net.IP。
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