我正在嘗試找出如何使用 golang 從 mailgun 接收電子郵件的文件附件。他們只提供 python 示例https://documentation.mailgun.com/en/latest/quickstart-receiving.html：# Handler for HTTP POST to http://myhost.com/messages for the route defined abovedef on_incoming_message(request): if request.method == 'POST': sender = request.POST.get('sender') recipient = request.POST.get('recipient') subject = request.POST.get('subject', '') body_plain = request.POST.get('body-plain', '') body_without_quotes = request.POST.get('stripped-text', '') # note: other MIME headers are also posted here... # attachments: for key in request.FILES: file = request.FILES[key] # do something with the file # Returned text is ignored but HTTP status code matters: # Mailgun wants to see 2xx, otherwise it will make another attempt in 5 minutes return HttpResponse('OK')我應該如何在 Go 中處理這部分，或者這個“文件”是什么類型？# attachments: for key in request.FILES: file = request.FILES[key]
1 回答
慕俠2389804
TA貢獻1719條經驗 獲得超6個贊
您可以讓 Mailgun 在您域的路由設置中發送回調請求示例： https: //app.mailgun.com/app/routes。要快速概覽，請在http://bin.mailgun.net上創建一個垃圾箱并輸入該 URL。
您將看到“轉發”操作的請求包含 multipart/form-data 主體，因此您使用http.Request.FormFile訪問附件：
http.HandleFunc("/callback", func(w http.ResponseWriter, r *http.Request) {
// r.FormFile and r.FormValue will call ParseMultipartForm
// automatically if necessary, but they ignore any errors. For
// robustness we do it ourselves.
if err := r.ParseMultipartForm(10 << 20); err != nil {
http.Error(w, err.Error(), 500)
return
}
// The "attachment-count" field reports how many attachments there are.
n, _ := strconv.Atoi(r.FormValue("attachment-count"))
// The file fields are then named "attachment-1", "attachment-2", ..., "attachment-n".
for i := 1; i <= n; i++ {
fieldName := fmt.Sprintf("attachment-%d", i)
file, header, err := r.FormFile(fieldName)
if err != nil {
http.Error(w, err.Error(), 500)
return
}
fmt.Printf("%s (%d bytes)\n", header.Filename, header.Size)
var _ = file // call file.Read() to read the file contents
}
})
對于 Mailgun 的測試負載，輸出將是：
crabby.gif (2785 bytes)
attached_файл.txt (32 bytes)
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