PHP 7.3.18MySQL 5.7.30這是相關的代碼，它立即失敗，所以我很感激它被糾正。第一個“如果”沒問題，但問題出在第二個和第三個。$targetcatid2、$targetcatid3、$targetweight2、$targetweight3 已正確聲明。目的是如果產品屬于 Category2 而不是 Category3，則重量將變為 Weight2，反之亦然。$row2=mysqli_fetch_array($select2);if($row2['category_id']== $targetcatid){ $row['product_weight']= $targetweight;}if($row2['category_id']== $targetcatid2 && !== $targetcatid3){ $row['product_weight']= $targetweight2;}if($row2['category_id']== $targetcatid3 && !== $targetcatid2){ $row['product_weight']= $targetweight3;}我最近的努力是：如果($row2['category_id']== $targetcatid){ $row['product_weight']= $targetweight; }如果($row2['category_id']== $targetcatid2 && $row2['category_id']!== $targetcatid3){ $row['product_weight']= $targetweight2; }elseif($row2['category_id']== $targetcatid3 && $row2['category_id']!== $targetcatid2){ $row['product_weight']= $targetweight3; }elseif($row2['category_id']== $targetcatid2 && $row2['category_id']== $targetcatid3){ $row['product_weight']= $targetweight3; }我發現新條件不起作用，即使是單獨使用也是如此。但是不明白為什么：elseif($row2['category_id'] == $targetcatid2 && $row2['category_id'] == $targetcatid3){ $row['product_weight'] = $targetweight3; }
1 回答
HUX布斯
TA貢獻1876條經驗 獲得超6個贊
您沒有正確理解 && 運算符。
而不是這個
if($row2['category_id']== $targetcatid2 && !== $targetcatid3){您應該分別比較條件。
if($row2['category_id']== $targetcatid2 && $row2['category_id'] !== $targetcatid3){- 1 回答
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