我想我已經回收了，大腦不再沸騰了。請告訴我如何刪除鍵中這些不需要的鍵？而且我的 foreach 似乎有點歪，我會很高興看到解決這個問題的提示。先感謝您。我對輸出有什么：Array( [0] => Array ( [0] => Array ( [id] => asdasd ) [1] => Array ( [server] => asdadsasd ) [2] => Array ( [login] => asdasdads ) [3] => Array ( [ip] => adsads ) [4] => Array ( [date] => dasadsads ) ) [1] => Array ( [0] => Array ( [id] => 12123123 ) [1] => Array ( [server] => 123213213 ) [2] => Array ( [login] => 321231123 ) [3] => Array ( [ip] => 213231213 ) [4] => Array ( [date] => 321213213 ) ))我需要做什么：Array( [0] => Array ( [id] => asdasd [server] => asdadsasd [login] => asdasdads [ip] => adsads [date] => dasadsads ) [1] => Array ( [id] => 12123123 [server] => 123213213 [login] => 321231123 [ip] => 213231213 [date] => 321213213 ))test2.php代碼：<?php //header('Content-Type: application/json'); $commands = array(); foreach($_POST as $key => $value) { foreach($_POST[$key] as $name => $val) { $commands[$name][] = array($key => $val); } } print_r($commands); //echo json_encode($commands, JSON_PRETTY_PRINT | JSON_UNESCAPED_UNICODE);?>我試過了$commands[$name] = array($key => $val);，但他愚蠢地替換了意思并替換了一個新的意思，當然。
1 回答
智慧大石
TA貢獻1946條經驗 獲得超3個贊
這對我有用->
<?php
header('Content-Type: application/json');
$commands = array();
foreach($_POST as $key => $value) {
foreach($_POST[$key] as $name => $val) {
$commands[$name][$key] = $val;
}
}
print_r($commands);
?>
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