我正在嘗試使用 php 創建附屬鏈接 geenrator，我正在使用以下代碼生成。但是只有當鏈接包含任何附屬標簽時，此代碼才在鏈接的最后添加 affid。如果我使用此鏈接，則“ https://www.flipkart.com/whirlpool-1-5-ton-5-star-split-inverter-ac-white/p/itmf8fb8a675505d?pid=ACNFE6K2BXFY6EKX ”它會向我發送相同的信息鏈接而不添加任何標簽。任何人都可以幫我解決這個問題嗎？$url = "https://www.flipkart.com/whirlpool-1-5-ton-5-star-split-inverter-ac-white/p/itmf8fb8a675505d?pid=ACNFE6K2BXFY6EKX"; $afftag = 'harshk'; //our affiliate ID $affstring = 'affid='; // url parameter for affiliate ID if (parse_url($url, PHP_URL_QUERY)): //check if link has query string if (strpos($affstring, $url) !== true) : //check if link already has affiliate ID $url = preg_replace("/(".$affstring.").*?(\z|&)/", "$1".$afftag."$2", $url); else: $url = $url.'&'.$affstring.$afftag; endif; else: $url = $url.'?'.$affstring.$afftag; endif;
1 回答
臨摹微笑
TA貢獻1982條經驗 獲得超2個贊
試試這是否有效
$url = "https://www.flipkart.com/whirlpool-1-5-ton-5-star-split-inverter-ac-white/p/itmf8fb8a675505d?pid=ACNFE6K2BXFY6EKX";
$afftag = 'harshk'; //our affiliate ID
$affstring = 'affid='; // url parameter for affiliate ID
if (parse_url($url, PHP_URL_QUERY)): //check if link has query string
if (strpos($affstring, $url) === true) : //check if link already has affiliate ID
$url = preg_replace("/(" . $affstring . ").*?(\z|&)/", "$1" . $afftag . "$2", $url);
else:
$url = $url . '&' . $affstring . $afftag;
endif;
else:
$url = $url . '?' . $affstring . $afftag;
endif;
解決方案#2
<?php
$urlStr = "https://www.flipkart.com/whirlpool-1-5-ton-5-star-split-inverter-ac-white/p/itmf8fb8a675505d?pid=ACNFE6K2BXFY6EKX";
$afftag = 'harshk'; //our affiliate ID
$affstring = 'affid'; // url parameter for affiliate ID
$url_components = parse_url($urlStr);
$params = [];
if (isset($url_components['query'])):
parse_str($url_components['query'], $params);
endif;
$url = "{$url_components['scheme']}://{$url_components['host']}{$url_components['path']}";
$params[$affstring] = $afftag;
$url .= "?" . http_build_query($params);
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