首頁猿問如何從數組中選擇最高的 3 個字符串值

如何從數組中選擇最高的 3 個字符串值

JavaScript

翻翻過去那場雪 2023-05-11 16:26:20

我有數組，其中有sequence number. 我只想從基于數組的數組中選擇前 3 個，sequence numbers而不是像 "sequesnce": "9.80.709.5This is my array這樣的序列號array1=[{ "orgId": 101, "dId": 494, "name": "Test1", "sequesnce": "6.408.06.0 Sequesnce Date : Mon 08/06/2019 (Sections: P4.00344) Italy CR"},{ "orgId": 102, "dId": 442, "name": "Test2", "sequesnce": "9.80.709.5 Sequesnce Date : Mon 06/04/2019 (Sections: P4.00344) Italy CR",},{ "orgId": 103, "sequesnce": "9.138.309.0 Sequesnce Date : Mon 06/03/2019 (Sections: P4.45600) Spain HR", "dId": 494, "name": "Test3",},{ "orgId": 103, "sequesnce": "8.208.409.0 Sequesnce Date : Mon 10/03/2019 (Sections: P4.568787) Spain HR", "dId": 494, "name": "Test3",},{ "orgId": 103, "sequesnce": "9.408.90.3 Sequesnce Date : Mon 08/06/2019 (Sections: P4.00344) Italy CR", "dId": 494, "name": "Test3",},我正在尋找輸出topThree={"sequesnce": "9.80.709.5 Sequesnce Date : Mon 06/04/2019 (Sections: P4.00344) Italy CR",},{"sequesnce": "9.408.90.3 Sequesnce Date : Mon 08/06/2019 (Sections: P4.00344) Italy CR",},{"sequesnce": "9.138.309.0 Sequesnce Date : Mon 06/03/2019 (Sections: P4.45600) Spain HR",},我試過這個function arrayMax(arr) {return arr.reduce(function (p, v) { return ( p > v ? p : v );});}]var maximo = arrayMax(obj); //return the high這讓我回來{ "orgId": 102, "dId": 442, "name": "Test2", "sequesnce": "9.80.709.5 Sequesnce Date : Mon 06/04/2019 (Sections: P4.00344) Italy CR",},此代碼返回單個數組而不是三個，并且不確定在所有情況下此邏輯是否有效。

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3 回答

BIG陽

TA貢獻1859條經驗獲得超6個贊

您可以排序String#localeCompare并選擇按點值列排序。

最后取前三項Array#slice。

const

? ? array = [{ orgId: 101, dId: 494, name: "Test1", sequesnce: "6.408.06.0 Sequesnce Date : Mon 08/06/2019 (Sections: P4.00344) Italy CR" }, { orgId: 102, dId: 442, name: "Test2", sequesnce: "9.80.709.5 Sequesnce Date : Mon 06/04/2019 (Sections: P4.00344) Italy CR" }, { orgId: 103, sequesnce: "9.138.309.0 Sequesnce Date : Mon 06/03/2019 (Sections: P4.45600) Spain HR", dId: 494, name: "Test3" }, { orgId: 103, sequesnce: "8.208.409.0 Sequesnce Date : Mon 10/03/2019 (Sections: P4.568787) Spain HR", dId: 494, name: "Test3" }, { orgId: 103, sequesnce: "9.408.90.3 Sequesnce Date : Mon 08/06/2019 (Sections: P4.00344) Italy CR", dId: 494, name: "Test3" }],

? ? top3 = array

? ? ? ? .sort((a, b) => b.sequesnce.localeCompare(a.sequesnce, undefined, { numeric: true, sensitivity: 'base' }))

? ? ? ? .slice(0, 3)

console.log(top3);

.as-console-wrapper { max-height: 100% !important; top: 0; }

反對回復 2023-05-11

慕慕森

TA貢獻1856條經驗獲得超17個贊

如果序列較短且前導值較高，則需要在排序前擴展元組 - 這不適用于 localeCompare

const maxLen = 4;

const expandTuple = tpl => {

tpl = tpl.split('.');

while (tpl.length < maxLen) tpl.unshift("000");

return tpl.map(x => x.padStart(3, "0")).join('.');

};

const array1 = [{ "orgId": 101, "dId": 494, "name": "Test1",

"sequence": "6.408.06.0 Sequence Date : Mon 08/06/2019 (Sections: P4.00344) Italy CR" },{"orgId": 102,"dId": 442,"name": "Test2",

"sequence": "9.80.709.5 Sequence Date : Mon 06/04/2019 (Sections: P4.00344) Italy CR",},{"orgId": 103,

"sequence": "99.1.1 NOTE THIS IS SHORTER Sequence Date : Mon 06/03/2019 (Sections: P4.45600) Spain HR","dId": 494,"name": "Test3",},{"orgId": 103,

"sequence": "8.208.409.0 Sequence Date : Mon 10/03/2019 (Sections: P4.568787) Spain HR","dId": 494,"name": "Test3",},{"orgId": 103,

"sequence": "9.408.90.3 Sequence Date : Mon 08/06/2019 (Sections: P4.00344) Italy CR","dId": 494, "name": "Test3", }

]

const three = array1.sort((a,b) => {

const aTub = a.sequence.split(" ")[0];

const bTub = b.sequence.split(" ")[0];

if (expandTuple(aTub)<expandTuple(bTub)) return 1

if (expandTuple(aTub)>expandTuple(bTub)) return -1

return 0;

}).slice(0,3)

console.log(three)

// ---- compare other solution which fails on the shorter sequence

console.log(array1

.sort((a, b) => b.sequence.localeCompare(a.sequence, undefined, { numeric: true, sensitivity: 'base' }))

.slice(0, 3)

)

反對回復 2023-05-11

肥皂起泡泡

TA貢獻1829條經驗獲得超6個贊

首先，使用Array.map，您可以僅生成項目對象數組sequesne。

并使用Array.sort，您可以按降序對數組進行排序。

并使用Array.splice，您可以從排序數組中提取前 3 項。

const array1 = [{

"orgId": 101,

"dId": 494,

"name": "Test1",

"sequesnce": "6.408.06.0 Sequesnce Date : Mon 08/06/2019 (Sections: P4.00344) Italy CR"

{

"orgId": 102,

"dId": 442,

"name": "Test2",

"sequesnce": "9.80.709.5 Sequesnce Date : Mon 06/04/2019 (Sections: P4.00344) Italy CR",

{

"orgId": 103,

"sequesnce": "9.138.309.0 Sequesnce Date : Mon 06/03/2019 (Sections: P4.45600) Spain HR",

"dId": 494,

"name": "Test3",

{

"orgId": 103,

"sequesnce": "8.208.409.0 Sequesnce Date : Mon 10/03/2019 (Sections: P4.568787) Spain HR",

"dId": 494,

"name": "Test3",

{

"orgId": 103,

"sequesnce": "9.408.90.3 Sequesnce Date : Mon 08/06/2019 (Sections: P4.00344) Italy CR",

"dId": 494,

"name": "Test3",

}

];

const sortedArr = array1.map(({ sequesnce }) => ({ sequesnce })).sort((a, b) => (b.sequesnce.localeCompare(a.sequesnce, undefined, { numeric: true, sensitivity: 'base'})));

const topCount = 3;

console.log(sortedArr.splice(0, topCount));

反對回復 2023-05-11

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如何從數組中選擇最高的 3 個字符串值

如何從數組中選擇最高的 3 個字符串值

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