我想解析一個包含非結構化文本的日志文件。我需要獲取核心 ID，在 json 中通過/失敗。自一周以來，我是編程的新手，我將不勝感激。AMPTTK v25: RSA ALL THREADS================RSACores X RSACores==============time: 421045.73Num Threads Available to process: 256Num Cores Requested to execute: 256TSC freq: 1600629120.0Memory allocated @ main (not all used by program): 3842.000000 MB RSA thread: : 0wrkspace addr : 7f0483400000wrkspace size : f00000 # cores: 16 core id: 0, 1, 2, 3, 4, 5, 6, 7, 64, 65, 66, 67, 68, 69, 70, 71, pass/fail: pass, pass, pass, pass, pass, pass, pass, pass, pass, pass, pass, pass, pass, pass, pass, pass, test ipc: 4.497, 4.503, 4.489, 4.476, 4.537, 4.471, 4.499, 4.459, 4.934, 4.946, 4.892, 4.933, 4.927, 4.927, 4.882, 4.886, aperf(MHz): 2826, 2814, 2826, 2826, 2826, 2826, 2827, 2826, 2909, 2909, 2909, 2909, 2909, 2909, 2909, 2909, aperf ipc: 2.392, 2.408, 2.397, 2.392, 2.397, 2.388, 2.397, 2.388, 2.341, 2.341, 2.340, 2.341, 2.341, 2.341, 2.340, 2.340, mce status: pass, pass, pass, pass, pass, pass, pass, pass, pass, pass, pass, pass, pass, pass, pass, pass,
1 回答
飲歌長嘯
TA貢獻1951條經驗 獲得超3個贊
我這樣做的一般方法是在日志文件中查找結構，然后將其提取出來。:查看您共享的數據，感興趣的行上有一個字符和十六個逗號分隔值。由于數據不是直接放入json的形式，所以我存儲在一個臨時字典中，然后將其轉換為json字符串。示例如下：
import json
# parse the log file and store in dictionary
raw_data = {}
with open('unstructured_data.txt') as log:
for line in log:
line = line.rstrip()
if line.count(':') == 1:
heading, data = line.split(':')
fields = data.split(',')
if len(fields) > 15:
raw_data[heading.lstrip()] = fields
# Put only data of interest in to another python dictionary
result_data = {}
for i in range(len(raw_data['core id'])):
result_data[raw_data['core id'][i].strip()] = raw_data['pass/fail'][i].strip()
# Convert python dictionary to json string
result_json = json.dumps(result_data)
print(result_json)
從您的日志文件中給出以下內容：
$ python3 parse_log.py
{"0": "pass", "1": "pass", "2": "pass", "3": "pass", "4": "pass", "5": "pass", "6": "pass", "7": "pass", "64": "pass", "65": "pass", "66": "pass", "67": "pass", "68": "pass", "69": "pass", "70": "pass", "71": "pass", "": ""}
雖然這不是一個完美的結果，但它應該有望通過實際數據得到改進。
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