如何計算特定長度字符串中的特定單詞。讓我們考慮一個字符串——“足球是一項偉大的運動，它是全世界最受歡迎的運動，它不僅是一種運動，而且還是一個萬國歡聚的節日，這也是最令人興奮的”。字符串的總長度是145。我喜歡統計每100個字符串中有多少個'is'。讓我們考慮長度為 100 的字符串的第一部分，即 - 'Football is a great game It is most popular game over the world It is not only a game but also'。在這里，我們在 100 個字符中找到了 3 個“是”。字符串的其余部分是 -'a festival of get together for the nations which is most exciting too' 其長度為 69，并且該長度中有 1 個“is”。我可以從字符串中找出給定單詞的數量，但不能從特定長度的字符串中找出。下面是我的代碼 -string word = "is";string sentence = "Football is a great game It is most popular game all over the world It is not only a game but also a festival of get together for the nations which is most exciting too";int count = 0;foreach (Match match in Regex.Matches(sentence, word, RegexOptions.IgnoreCase)){ count++;}Console.WriteLine("{0}" + " Found " + "{1}" + " Times", word, count);`輸入：string - '足球是一項偉大的運動，它是全世界最受歡迎的運動，它不僅是一項運動，也是一個萬國歡聚的節日，也是最令人興奮的'詞-'是'長度 - 100輸出：在第一部分：給定單詞的數量 = 3在第二部分：給定單詞的數量 = 1
2 回答
倚天杖
TA貢獻1828條經驗 獲得超3個贊
試試這個代碼：
public class JavaApplication22 {
public static void main(String[] args) {
String str = "Football is a great game It is most popular game all over the world It is not only a game but also a festival of get together for the nations which is most exciting too";
String pattern = "is";
int count = 0;
int a = 0;
while((a = str.indexOf(pattern, a)) != -1){
a += pattern.length();
count++;
}
System.out.println("Count is : " + count);
}
}
肥皂起泡泡
TA貢獻1829條經驗 獲得超6個贊
創建一個具有所需長度的子字符串，然后使用 linq 進行計數。
int length = 100;
string word = "is";
string sentence = "Football is a great game It is most popular game all over the world It is not only a game but also a festival of get together for the nations which is most exciting too";
//Substring with desired length
sentence = sentence.Substring(0, length);
int count = 0;
//creating an array of words
string[] words = sentence.Split(Convert.ToChar(" "));
//linq query
count = words.Where(x => x == word).Count();
Debug.WriteLine(count);
對于第二部分，創建一個從 100 開始到字符串末尾的子字符串。
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