我的actions.js文件中定義了一個 thunk：export const myThunk = (param1, param2, param3) => {   return dispatch => {      dispatch({type: types.myThunkType})      fetch(`https://mockurl.com?param1=${param1}&param2=${param2}&param3=${param3}`)      .then(response => response.json())      .then(data => {         dispatch({type: types.everythingsAllRight, payload: data.results})      })   }}當我從 React 組件分派它時，一切都像魅力一樣。在我的component.js我們有這樣的東西：import myThunk from './actions/actions.js'const dispatch = useDispatch()return (   <button onClick={() => {dispatch(myThunk(props.param1, props.param2, props.param3)}>)但是當我嘗試從中間件使用相同的 thunk 時，如下所示：   store.dispatch(anPlainObjectActionDefinedInActionsJsToo(param1, param2, false))   .then(() => {       store.dispatch({         type: types.anotherImportantActionType,         payload: {            thisData: someData,            thatData: someOtherData         }      })   })   .then(store.dispatch(myThunk(param1, param2, param3)))我收到此錯誤：Unhandled Rejection (Error): Actions must be plain objects. Use custom middleware for async actions.錯誤是命中處理動作類型的中間件myThunkType：Unhandled Rejection (Error): Actions must be plain objects. Use custom middleware for async actions.? 3 stack frames were collapsed.(anonymous function)src/Store/middleware/middlewareThatDealsWithMyThunkTupeActionType.js:9   6 | }   7 | if (action.type !== types.myThunkType &&   8 |    action.type !== types.anotherType) {>  9 |    return next(action)     | ^  10 | }  11 | 因為它不能“返回下一個動作”。有什么跡象表明我做錯了嗎？編輯：在調試中檢查，我發現發送的 thunk 在遇到中間件時看起來像這樣：https: //imgur.com/s7AS8eD