我正在使用此代碼對單詞和整數對進行排序，按整數對對進行排序（降序）對元組進行排序后，如何僅將字符串值保存在 String [] 數組中？我在這里找到了代碼，因為我是新來的，所以我無法在同一頁面上發表評論。（@Elliott Frisch）如何按頻率對單詞進行排序 public Tuple(int count, String word) { this.count = count; this.word = word;}@Overridepublic int compareTo(Tuple o) { return new Integer(this.count).compareTo(o.count);}public String toString() { return word + " " + count;}}public static void main(String[] args) {String[] words = { "the", "he", "he", "he", "he", "he", "he", "he", "he", "the", "the", "with", "with", "with", "with", "with", "with", "with" };// find frequenciesArrays.sort(words);Map<String, Integer> map = new HashMap<String, Integer>();for (String s : words) { if (map.containsKey(s)) { map.put(s, map.get(s) + 1); } else { map.put(s, 1); }}List<Tuple> al = new ArrayList<Tuple>();for (Map.Entry<String, Integer> entry : map.entrySet()) { al.add(new Tuple(entry.getValue(), entry.getKey()));}Collections.sort(al);System.out.println(al);}
2 回答
白衣非少年
TA貢獻1155條經驗 獲得超0個贊
如果它必須是數組，你去：
Collections.sort(al);
String[] wordsResult = new String[al.size()];
int i = 0;
for (Tuple tuple : al) {
wordsResult[i++] = tuple.word;
}
Stream.of(wordsResult).forEach(System.out::println);
System.out.println(al);
溫溫醬
TA貢獻1752條經驗 獲得超4個贊
您還可以使用 Stream-API 對這個 ArrayList 進行排序
Object[] arr = al.stream()
.sorted(Comparator.comparing(Tuple::getCount).reversed())//sort counts as per count
.map(Tuple::getWord) //mapping to each count to word
.toArray(); //collect all words to array
System.out.println(Arrays.toString(arr));
你也可以把這些話收藏起來List<String>
List<String> arr =al.stream()
.sorted(Comparator.comparing(Tuple::getCount).reversed())//sort counts as per count
.map(Tuple::getWord) //mapping to each count to word
.collect(Collectors.toList())//Collect to List
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