你能幫我解決這個問題嗎？在 PHP 中刪除第 4 個和第 5 個數組的函數是什么。Array( [0] => Array ( [10] => 98 [11] => 1 [433438] => 8 ) [1] => Array ( [10] => 98 [11] => 1 [433438] => 1 ) [2] => Array ( [13] => 98 [11] => 2 [433438] => 8 ) [3] => Array ( [14] => 98 [11] => 2 [433438] => 1 ) [4] => Array ( [10] => 18 [11] => 1 ) [5] => Array ( [14] => 18 [11] => 2 ))提前致謝。
2 回答
30秒到達戰場
TA貢獻1828條經驗 獲得超6個贊
$base = [
[10 => 98, 11 => 1, 433438 => 8],
[10 => 98, 11 => 1, 433438 => 1],
[13 => 98, 11 => 2, 433438 => 8],
[14 => 98, 11 => 2, 433438 => 1],
[10 => 18, 11 => 1],
[14 => 18, 11 => 2],
];
$invalid = [];
for ($i = 0; $i <= count($base) - 1; $i++) {
for ($j = 0; $j <= count($base) - 1; $j++) {
$refCount = count($base[$j]);
$interSectCount = count(array_intersect(array_keys($base[$i]), array_keys($base[$j])));
if (count($base[$i]) !== $refCount && $interSectCount === $refCount) {
$invalid[] = $j;
}
}
}
foreach ($invalid as $item) {
unset($base[$item]);
}
喵喵時光機
TA貢獻1846條經驗 獲得超7個贊
您可以使用array_pop()消除數組最后一個元素的函數，但如果您使用它兩次，您將獲得所需的結果
<?php
$data = [
1 => [1,2],
2 => [1,3],
3 => [1,4]
];
$value = array_pop($data);
$value = array_pop($data);
?>
輸出
Array
(
[1] => Array
(
[0] => 1
[1] => 2
)
)
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