我對 Laravel 模型關系有疑問。我需要讓用戶創建新卡車。但是，我需要將制造商的字段存儲為 ID，而不是標題。所以我決定制作兩個具有一對多關系的表（制造商和卡車）（制造商有多輛卡車，而一輛卡車有一個制造商）。這是遷移文件。制造商表：public function up(){    Schema::create('manufacturers', function (Blueprint $table) {        $table->bigIncrements('id');        $table->string('manufacturer');        $table->timestamps();    });}卡車表：public function up(){    Schema::create('trucks', function (Blueprint $table) {        $table->bigIncrements('id');        $table->unsignedBigInteger('make_id');        $table->unsignedInteger('year');        $table->string('owner');        $table->unsignedInteger('owner_number')->nullable();        $table->text('comments')->nullable();        $table->foreign('make_id')->references('id')->on('manufacturers');        $table->timestamps();    });}Manufacturer.php模型：namespace App;use Illuminate\Database\Eloquent\Model;class Manufacturer extends Model{/** * @var string */protected $table = 'manufacturers';/** * @var array */protected $fillable = [    'manufacturer', ];public function trucks(){    return $this->hasMany(Truck::class);}}Truck.php 模型：namespace App;use Illuminate\Database\Eloquent\Model; class Truck extends Model { /** * @var string */protected $table = 'trucks';/** * @var array */protected $fillable = [    'make_id', 'year', 'owner', 'owner_number', 'comments',];public function manufacturer(){    return $this->belongsTo(Manufacturer::class);}}控制器文件：public function index(){    $trucks = Truck::all();    return view('trucks.index')->with('trucks', $trucks);}索引.blade.php@foreach($trucks as $truck)            <tbody>            <tr>                <td>{{$truck->make_id}}</td> //I need this one to show manufacturers title                <td>{{$truck->year}}</td>                <td>{{$truck->owner}}</td>                <td>{{$truck->owner_number}}</td>                <td>{{$truck->comments}}</td>            </tr>            </tbody>            @endforeach此視圖現在顯示 id。我需要做什么來顯示制造商標題（manufacturers.manufacturer）而不是 id？謝謝大家！