我想把上傳文件路徑返回到前端保存,但是后臺php文件里的js沒有執行,前臺input標簽里的value值一直為空后臺acceptfile.php代碼如下:<?php if(!isset($_REQUEST['filename']))
{ exit('No file');
} else{ $upload_path = dirname(__FILE__).'/audio';
date_default_timezone_set("Asia/Shanghai"); $filename = $_REQUEST['filename'].rand(0,10000).date('YmdHis'); $fp = fopen($upload_path."/".$filename.".wav", "wb"); $audiosrc=$upload_path."/".$filename.".wav";
echo "<script language='javascript'>parent.send_form.audiosrc.value='$audiosrc';</script>";
echo "<script language='javascript'>alert('上傳成功');</script>";
fwrite($fp, file_get_contents('php://input'));
fclose($fp); exit('done');
}
?>前端index.php里form表單:<form id="send_form" method="post" enctype="multipart/form-data">
...
<input type="hidden" name="audiosrc" id="audiosrc" value="" />
<input type="submit" class="send" id="send" value="提交">
</form>
請問問題出在哪,文件是有保存到相應的文件夾里的,就是路徑沒法返回到前端form表單里?
SMILET
2023-04-18 18:14:50