這是菜單當中的打開命令的代碼def openfile(self):   p1=END   oname=askopenfilename(filetypes=[("文本文檔","*.txt")])   if oname:    for line in fileinput.input(oname):     self.st.insert(p1,line)    self.t.title(oname) def savefile(self):   sname=asksaveasfilename()   if sname:    ofp=open(sname,"w")    ofp.write(self.st.get(1.0,END))    ofp.flush()    ofp.close()    self.t.title(sname)