我卡住了?？雌饋磉@應該有效，但事實并非如此。我正在嘗試訪問對象的鍵值，但它不起作用。我以前做過這個，并且在堆棧溢出和其他地方閱讀了很多東西，但它仍然不起作用。這是我的代碼：  var validate = UrlFetchApp.fetch(url, options);    Logger.log('validate = ' + validate);  Logger.log("validate['response'] = " + validate["response"]);  Logger.log('validate.response = ' + validate.response);  Logger.log("validate.['done'] = " + validate["done"]);  Logger.log("validate.done = " + validate.done);    var validateObj = JSON.stringify(JSON.parse(validate));    Logger.log("validateObj = " + validateObj);  Logger.log("validateObj.response = " + validateObj.response);  Logger.log("validateObj.done = " + validateObj.done);這是日志：validate = {  "done": true,  "response": {    "@type": "type.googleapis.com/google.apps.script.v1.ExecutionResponse",    "result": "Invalid Full Name.  Please enter a valid Full Name."  }}validate['response'] = undefinedvalidate.response = undefinedvalidate.['done'] = undefinedvalidate.done = undefinedvalidateObj = {"done":true,"response":{"@type":"type.googleapis.com/google.apps.script.v1.ExecutionResponse","result":"Invalid Full Name.  Please enter a valid Full Name."}}validateObj.response = undefinedvalidateObj.done = undefined使用括號表示法時，我也嘗試過使用單引號和雙引號。誰能幫我看看錯誤？