我開發了Spring Boot + Spring Data Jpa Rest示例。我開發了下面的代碼并給出了下面的錯誤，即使我無法啟動 Swagger 也給我錯誤。{ "timestamp": "2019-07-22T15:29:04.487+0000", "status": 500, "error": "Internal Server Error", "message": "Could not write JSON: Infinite recursion (StackOverflowError); nested exception is com.fasterxml.jackson.databind.JsonMappingException: Infinite recursion (StackOverflowError) (through reference chain: java.util.ArrayList[0]->com.example.demo.entity.Employee[\"department\"]->com.example.demo.entity.Department$HibernateProxy$muKgohop[\"employees\"])", "path": "/employees/findEmployees/john"}RangeError：在 Mt.map (immutable.js:4401) 在 e (utils.js:64) 在 immutable.js:3016 在 immutable.js:2699 在 ft.__iterate (immutable.js:2206)在 Mt.__iterate (immutable.js:2698) 在 r.Lt.r.__iterateUncached (immutable.js:3015) 在 le (immutable.js:604) 在 rJ__iterate (immutable.js:274) 在 r.forEach (immutable .js:4381)Employee.java@Builder@Data@AllArgsConstructor@NoArgsConstructor@Entitypublic class Employee implements Serializable{ private static final long serialVersionUID = 1L; @Id @GeneratedValue(strategy = GenerationType.IDENTITY) @Column(name="EMPLOYEE_ID") private Long employeeId; @Column(name="FIRST_NAME") private String firstName; @Column(name="LAST_NAME") private String lastName; @Column(name="EMAIL_ID") private String email; @Column(name="STATUS") private String status; @Column(name="BIRTH_DATE") private LocalDate birthDate; @Column(name="PROJECT_ASSOCIATION") private Integer projectAssociation; @Column(name="GOAL_COUNT") private Integer goalCnt; @ManyToOne(fetch = FetchType.LAZY) @JoinColumn(name = "DEPT_ID", nullable = false) private Department department;}
2 回答
搖曳的薔薇
TA貢獻1793條經驗 獲得超6個贊
我簡單地添加了它@JsonIgnore并且它工作了。
@OneToMany(fetch = FetchType.LAZY, mappedBy = "department")
@JsonIgnore
private Set<Employee> employees;
還
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "DEPT_ID", nullable = false)
@JsonIgnore
private Department department;
守著一只汪
TA貢獻1872條經驗 獲得超4個贊
如果您想在父實體的 JSON 響應中保留值，您可以執行以下操作：
//without @JsonIgnore
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "DEPT_ID", nullable = false)
private Department department;
還
//with @JsonIgnore
@OneToMany(fetch = FetchType.LAZY, mappedBy = "department")
@JsonIgnore
private Set<Employee> employees;
以及沒有員工值的子實體中的 @Override hashCode() 方法，如下所示：
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + ((departmentId == null) ? 0 : departmentId .hashCode());
result = prime * result + ((departmentName == null) ? 0 : departmentName.hashCode());
result = prime * result + ((departmentCode == null) ? 0 : departmentCode.hashCode());
return result;
}
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