我正在學習 Python 并且正在構建紙牌游戲（似乎很常見并且對初學者來說很好）。我有一個名為打印隨機卡的Cartas 方法的類。imprimir()然后我有一個名為的函數create_deck()，它用 52 張卡片填充一個空列表。import randomclass Cards: def __init__(self, Value = random.choice([1,2,3,4,5,6,7,8,9,10,11,12,13]), Suit = random.choice(["Diamonds", "Hearts", "Clubs", "Spades"])): self.Value = Value self.Suit = Suit def imprimir(self): if self.Value == 11: print("J of " + self.Suit) elif self.Value == 12: print("Queen of " + self.Suit) elif self.Value == 13: print("King of " + self.Suit) else: print(str(self.Value) + " de " + self.Suit)card = Cards()card.imprimir()def create_deck(): list_deck = [] list_numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13] lista_suit = ["Diamonds", "Hearts", "Clubs", "Spades"] for number in list_numbers: for suit in list_suit : if card == 11: card = f'J of {suit}' list_deck.append(card) elif number == 12: card = f'Queen of {suit}' list_deck.append(card) elif number == 13: card = f'King of {suit}' list_deck.append(card) else: card = f'{number} of {suit}' list_deck.append(card) print(list_deck)print(create_deck())我想create_deck()用 的新實例填充空列表，Cards()而不是只用字符串填充它，例如： [card1, card2, card3, etc etc,..card52]。我怎樣才能做到這一點？
2 回答
呼喚遠方
TA貢獻1856條經驗 獲得超11個贊
除了 for 循環，您還可以使用列表推導式在一行中完成：
list_deck = [Cards(num, suit) for num in list_numbers for suit in list_suit]
如果您更喜歡像以前一樣使用 for 循環，那么只需使用您的類將項目添加到列表中：
for number in list_numbers:
for suit in list_suit :
list_deck.append(Cards(number, suit))
如果你想打印你的 Cards 對象，那么你需要為你的類實現repr函數。
def __repr__(self):
if self.Value == 11:
return("J of " + self.Suit)
elif self.Value == 12:
return("Queen of " + self.Suit)
elif self.Value == 13:
return("King of " + self.Suit)
else:
return(str(self.Value) + " de " + self.Suit)
一只斗牛犬
TA貢獻1784條經驗 獲得超2個贊
你可以這樣生成它：
cards = [Cards() for card in range(n_cards)]
這樣，對于可迭代對象中的每個元素range(n_cards)（它只是從 0 到獨占 n_cards (0, 1, 2... n_cards - 1) 的范圍），您將向Cards()列表中添加一個新對象。
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