我需要得到這個 json 響應的“ids”，問題是，有很多字典里面有一個字典列表，我該怎么做？？（PS：len（items）是 20，所以我需要以字典的形式獲取 20 個 id。{'playlists': {'href': 'https://api.spotify.com/v1/search?query=rewind-The%25&type=playlist&offset=0&limit=20', 'items': [{'collaborative': False, 'description': 'Remember what you listened to in 2010? Rewind and rediscover your favorites.', 'external_urls': {'spotify': 'https://open.spotify.com/playlist/37i9dQZF1DXc6IFF23C9jj'}, 'href': 'https://api.spotify.com/v1/playlists/37i9dQZF1DXc6IFF23C9jj', 'id': '37i9dQZF1DXc6IFF23C9jj', 'images': [{'height': None, 'url': 'https://i.scdn.co/image/ab67706f0000000327ba1078080355421d1a49e2', 'width': None}], 'name': 'Rewind - The Sound of 2010', 'owner': {'display_name': 'Spotify', 'external_urls': {'spotify': 'https://open.spotify.com/user/spotify'}, 'href': 'https://api.spotify.com/v1/users/spotify', 'id': 'spotify', 'type': 'user', 'uri': 'spotify:user:spotify'}, 'primary_color': None, 'public': None, 'snapshot_id': 'MTU5NTUzMTE1OSwwMDAwMDAwMGQ0MWQ4Y2Q5OGYwMGIyMDRlOTgwMDk5OGVjZjg0Mjdl', 'tracks': {'href': 'https://api.spotify.com/v1/playlists/37i9dQZF1DXc6IFF23C9jj/tracks', 'total': 100}, 'type': 'playlist', 'uri': 'spotify:playlist:37i9dQZF1DXc6IFF23C9jj'},我試圖通過這個來解決它：dict={'id':''}for playlists in playlist_data['playlists']: for items in playlists['items']: for item in items: for dic in range(len(item)): for id in dic['id']: dict.update('id') print(dict)我收到此錯誤：TypeError: string indices must be integers ```
2 回答
ibeautiful
TA貢獻1993條經驗 獲得超6個贊
嘗試這樣的事情：
ids = [item["id"] for item in json_data["playlists"]["items"]]
這稱為列表理解。
您想要遍歷鍵"items"內的所有內容"playlists"。
您可以訪問該項目列表：
json_data["playlists"]["items"]
然后迭代項目中的每個項目：
for item in json_data["playlists"]["items"]
然后你訪問"id"每個項目的：
item["id"]
交互式愛情
TA貢獻1712條經驗 獲得超3個贊
您可以使用對象的鍵索引對象。我可以看到對象中有兩個地方存在 id。要檢索這兩個 ID 并將它們存儲在字典格式中，您可以使用以下方法 -
_json = {
'playlists': {
'href': 'https://api.spotify.com/v1/search?query=rewind-The%25&type=playlist&offset=0&limit=20',
'items': [{
'collaborative': False,
'description': 'Remember what you listened to in 2010? Rewind and rediscover your favorites.',
'external_urls': {
'spotify': 'https://open.spotify.com/playlist/37i9dQZF1DXc6IFF23C9jj'
},
'href': 'https://api.spotify.com/v1/playlists/37i9dQZF1DXc6IFF23C9jj',
'id': '37i9dQZF1DXc6IFF23C9jj',
'images': [{
'height': None,
'url': 'https://i.scdn.co/image/ab67706f0000000327ba1078080355421d1a49e2',
'width': None
}],
'name': 'Rewind - The Sound of 2010',
'owner': {
'display_name': 'Spotify',
'external_urls': {
'spotify': 'https://open.spotify.com/user/spotify'
},
'href': 'https://api.spotify.com/v1/users/spotify',
'id': 'spotify',
'type': 'user',
'uri': 'spotify:user:spotify'
},
'primary_color': None,
'public': None,
'snapshot_id': 'MTU5NTUzMTE1OSwwMDAwMDAwMGQ0MWQ4Y2Q5OGYwMGIyMDRlOTgwMDk5OGVjZjg0Mjdl',
'tracks': {
'href': 'https://api.spotify.com/v1/playlists/37i9dQZF1DXc6IFF23C9jj/tracks',
'total': 100
},
'type': 'playlist',
'uri': 'spotify:playlist:37i9dQZF1DXc6IFF23C9jj'
}, ]
}
}
res_dict = {'id':[items['id'], items['owner']['id']] for items in _json['playlists']['items']}
print(res_dict)
輸出 ：
{'id': ['37i9dQZF1DXc6IFF23C9jj', 'spotify']}
如果您不需要 json 對象中存在的第二個 id，您可以將其從 res_dict 上方刪除并將其修改為 -
res_dict = {'id':items['id'] for items in _json['playlists']['items']}
這只會獲取items數組中存在的 id 作為任何元素的鍵，而不是任何進一步嵌套的 id（比如 items[i]->owner->id 不會像第一個案例那樣出現在最終資源中）。
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