這是一個簡單的 pygame 代碼，我在其中插入了一個屏幕，一個粉紅色的矩形并嘗試移動它。pygame 窗口中的矩形沒有移動。這意味著“**”內的代碼無法正常工作。我該如何解決？import pygame, syspygame.init()width = 800height = 600pink = (244,133,227)player_pos = [400, 300]player_size = 50screen = pygame.display.set_mode((width,height))game_over = Falsewhile not game_over: for event in pygame.event.get(): if event.type == pygame.QUIT: sys.exit()** if event.type == pygame.KEYDOWN: x = player_pos[0] y = player_pos[1] if event.type == pygame.K_LEFT: x -= player_size elif event.type == pygame.K_RIGHT: x += player_size player_pos = [x, y] screen.fill((0,0,0)) ** pygame.draw.rect(screen, pink, (player_pos[0], player_pos[1], player_size, player_size)) pygame.display.update()
1 回答
元芳怎么了
TA貢獻1798條經驗 獲得超7個贊
密鑰存儲在?key屬性中，而不是type屬性中。見pygame.event：
if?event.key?==?pygame.K_LEFT:
看例子：
import pygame, sys
pygame.init()
width = 800
height = 600
pink = (244,133,227)
player_pos = [400, 300]
player_size = 50
screen = pygame.display.set_mode((width,height))
game_over = False
while not game_over:
? ? for event in pygame.event.get():
? ? ? ? if event.type == pygame.QUIT:
? ? ? ? ? ? sys.exit()
? ? ? ? if event.type == pygame.KEYDOWN:
? ? ? ? ? ? x = player_pos[0]
? ? ? ? ? ? y = player_pos[1]
? ? ? ? ? ? if event.key == pygame.K_LEFT:
? ? ? ? ? ? ? ? x -= player_size
? ? ? ? ? ? elif event.key == pygame.K_RIGHT:
? ? ? ? ? ? ? ? x += player_size
? ? ? ? ? ? player_pos = [x, y]
? ? screen.fill((0,0,0))??
? ? pygame.draw.rect(screen, pink, (player_pos[0], player_pos[1], player_size, player_size))
? ? pygame.display.update()
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