首頁猿問如何使用循環索引獲取對象中的值

如何使用循環索引獲取對象中的值

JavaScript

偶然的你 2023-03-24 17:11:39

我有一個提交多個數據的 javascript 表單集，如果我得到所有的發布數據，我有類似下面的內容firstname1: "John",lastname1: "Doe",firstname2: "Mary",lastname2: "Allinson",firstname3: "David"lastname3: "Mark",eventDesctiption: "Lorem Ipsum...",eventDate: "Lorem Ipsum..."在本例中，我有一個隱藏字段，其中包含提交的姓名數量；它的 3. 我希望能夠循環遍歷名稱并將它們放入對象數組中，然后再發布到 API，我希望能夠實現以下目標{eventDesctiption: "Lorem Ipsum...",eventDate: "Lorem Ipsum...",people: [ {firstname: "John", lastname: "Doe"}, {firstname: "Mary", lastname: "Allinson"}, {firstname: "David", lastname: "Mark"}, ]}我嘗試了下面的方法，但它似乎將索引與值連接起來，這不是我想要的peopleArray = new Array();for(var i=1; i<=no_of_ben; i++){ var peopleObject = {}; peopleObject.firstname = data.firstname + 'i';peopleObject.lastname = data.lastname + 'i'; peopleArray.push(peopleObject); }如何在不連接索引的情況下執行此操作

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3 回答

一只斗牛犬

TA貢獻1784條經驗獲得超2個贊

const input = {

firstname1: "John",

lastname1: "Doe",

firstname2: "Mary",

lastname2: "Allinson",

firstname3: "David",

lastname3: "Mark",

eventDescription: "Lorem Ipsum...",

eventDate: "Lorem Ipsum..."

};

const output = {

eventDescription: input.eventDescription,

eventDate: input.eventDate,

people: []

};

const peopleCount = 3; // You said you have this one somewhere

for (let i = 1; i <= peopleCount; i++) {

const onePerson = {

firstname: input['firstname' + i],

lastname: input['lastname' + i]

};

output.people.push(onePerson);

}

console.log(output);

反對回復 2023-03-24

喵喔喔

TA貢獻1735條經驗獲得超5個贊

嘗試這個。應該是工作

peopleArray = new Array();

data = {

firstname1: 'king', lastname1: 'James',

firstname2: '2ndName', lastname2: '2ndLast',

firstname3: 'alice', lastname3: 'bambam'

};

for(var i=1; i<=3; i++){

var x = 'firstname';

var y = 'lastname';

var peopleObject = {};

x = x + i;

y = y + i;

peopleObject.firstname = data[x];

peopleObject.lastname = data[y];

peopleArray.push(peopleObject);

}

console.log(peopleArray);

反對回復 2023-03-24

慕雪6442864

TA貢獻1812條經驗獲得超5個贊

檢查這是否有效..

peopleArray = new Array();

for(var i=1; i<=no_of_ben; i++){

var peopleObject = {};

peopleObject.firstname = data['firstname' + 'i'];

peopleObject.lastname = data['lastname' + 'i'];

peopleArray.push(peopleObject);

}

將data.firstname + 'i'替換為data['firstname' + 'i']

反對回復 2023-03-24

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如何使用循環索引獲取對象中的值

如何使用循環索引獲取對象中的值

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