輸入123、+123、-123、（空格）+123，返回是有效整數；輸入123.4、.5、-.5、+.5、（空格）0.2，返回的是有效double型；輸入123.4.5.6、f123、-（空格）0.2、-0.（空格）2、0.+2等返回的是無效數據。我的代碼如下，思路不成熟，所以效果沒達到，麻煩高手把把關。int main(int argc, char **argv){char buffer[LINELEN];char *fgets_rtn = NULL;int i;int point_flag = 0;for ( i = 0; buffer[i] != 0 ;){fgets_rtn = fgets(buffer, LINELEN, stdin);if ( NULL == fgets_rtn ){return 0;}if ( '\n' == buffer[strlen(buffer) -1]){buffer[strlen(buffer) -1] = '\0';}if (i==0&&(isdigit(buffer[i]) == 1||isspace(buffer[i]) == 1||buffer[i]=='+'||buffer[i]=='-')){i++;}if (buffer[i]=='.'){i++;point_flag++;}if (isdigit(buffer[i]) == 1){ i++;if (point_flag == 1){printf( "%s is a valid double\n", buffer);}if (point_flag > 1){printf( "%s is not a valid number...\n", buffer);} if (point_flag == 0){printf("%s is a valid integer\n",buffer);}}else{printf("%s is not a valid number\n",buffer);}}return 0;}
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呼如林
TA貢獻1798條經驗 獲得超3個贊
抽出來判斷部分。
int isValidInt(char* str){ while (isspace(str) || *str == '\0') ++str; if (*str == '\0') return 0; if (*str == '+' || *str == '-') ++str; while (*str != '\0') { if (!isdigit(*str)) return 0; ++str; } return 1;} |
大概這樣。
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