我想做的是所以我基本上想做的是每次一輛車越過終點 它說哪輛車有一個但我想做的是每次第一輛車獲勝并且第二輛車越過終點線我想要它說哪輛車排在第二位和第三位等等import pygame, randompygame.init()# musicmusic = pygame.mixer.music.load(“image/Led Zeppelin - Rock And Roll (Alternate Mix) (Official Music Video).mp3”)pygame.mixer.music.play(-1)#Setting up our colors that we are going to useGREEN = (20, 255, 140)GREY = (210, 210, 210)WHITE = (255, 255, 255)RED = (255, 0, 0)PURPLE = (255, 0, 255)BLACKWHITE =(96, 96, 96)SCREENWIDTH = 400SCREENHEIGHT = 500size = (SCREENWIDTH, SCREENHEIGHT)screen = pygame.display.set_mode(size)pygame.display.set_caption("Car Racing")Icon = pygame.image.load("image/redca_iconr.png")pygame.display.set_icon((Icon))# This will be a list that will contain all the sprites we intend to use in our game.#all_sprites_list = pygame.sprite.Group()#playerplayerIMG = pygame.image.load("image/red_racecar.png")playerX = 250playerY = 450playerCar_position = 0#player2playerIMG_two = pygame.image.load("image/greencar.png")playerX_two = 150playerY_two = 450playerCar_position_two = 0#player3playerIMG_three = pygame.image.load("image/Orangecar.png")playerX_three = 50playerY_three = 450playerCar_position_three = 0#player4playerIMG_four = pygame.image.load("image/yellow_car.png")playerX_four = 200playerY_four = 450playerCar_position_four = 0#Putting cars to the screendef player(x, y): screen.blit(playerIMG, (x, y))def player_two(x, y): screen.blit(playerIMG_two, (x, y))def player_three(x, y): screen.blit(playerIMG_three, (x, y))def player_four(x, y): screen.blit(playerIMG_four, (x, y))
2 回答
哈士奇WWW
TA貢獻1799條經驗 獲得超6個贊
所以，你得到的代碼有效，唯一的問題是當汽車與終點線相交時，你只在屏幕上顯示文本
因此，每幀都有一個字符串放在屏幕上，當汽車越過這條線時，將字符串更改為那輛車
#put these outside the game loop
finish_text = ""
font2 = pygame.font.SysFont("Papyrus", 45)
players_finished = 0
placings = ["1st", "2nd", "3rd", "4th"]
while running: #game loop
...
# Did anyone cross the line?
if (finish_line_rect.collidepoint(playerX, playerY)):
if finish_text[:9] != "Player 1": #so it doesnt do this every frame the car is intersecting
finish_text = "Player 1 is " + placings[players_finished]
players_finished += 1
print("Player (one) has crossed into finish line!")
elif (finish_line_rect.collidepoint(playerX_two , playerY_two)):
if finish_text[:9] != "Player 2":
print("Player one has crossed into finish line first other car lost!")
finish_text = "Player 2 is " + placings[players_finished]
players_finished += 1
elif (finish_line_rect.collidepoint(playerX , playerY)):
if finish_text[:9] != "Player 3":
print("Player two has crossed into finish line first other car lost!")
finish_text = "Player 3 is " + placings[players_finished]
players_finished += 1
elif (finish_line_rect.collidepoint(playerX_two, playerY_two)):
if finish_text[:9] != "Player 4":
print("Player two has crossed into finish line first other car lost!")
finish_text = "Player 4 is " + placings[players_finished]
players_finished += 1
if finish_text != "": #test to see if there is anything to put on screen
text2 = font2.render(finish_text, 5, (255, 99, 7))
screen.blit(text2, (135 - (text2.get_width() / 5), 95))
pygame.display.flip()
筆記。還沒有測試過
UYOU
TA貢獻1878條經驗 獲得超4個贊
我從未使用過 pygame，所以不知道是否有內置函數。但是，您可以輕松地制作一個計數器。
#this is all in your while loop
if playerY<50 or playerY_two<50 or playerY_three<50 or playerY_four<50:
count+=1
if count == 1:
if playerY<50:
print('playerY first place')
playerY=10000
if playerY_two<50:
print('playerY_two first place')
playerY_two=100000
if playerY_three<50:
print('playerY_three first place')
playerY_three=100000
if playerY_four<50:
print('playerY_four first place')
playerY_four=1000000
if count == 2:
if playerY<50:
print('playerY second place')
playerY=10000
if playerY_two<50:
print('playerY_two seoncd place')
playerY_two=100000
if playerY_three<50:
print('playerY_three second place')
playerY_three=100000
if playerY_four<50:
print('playerY_four second place')
playerY_four=1000000
if count == 3:
if playerY<50:
print('playerY third place')
playerY=10000
if playerY_two<50:
print('playerY_two third place')
playerY_two=100000
if playerY_three<50:
print('playerY_three third place')
playerY_three=100000
if playerY_four<50:
print('playerY_four third place')
playerY_four=1000000
if count == 4:
if playerY<50:
print('playerY 4th place')
playerY=10000
if playerY_two<50:
print('playerY_two 4th place')
playerY_two=100000
if playerY_three<50:
print('playerY_three 4th place')
playerY_three=100000
if playerY_four<50:
print('playerY_four 4th place')
playerY_four=1000000
break
你可以創建一個類/函數來將上面的全部內容寫成 4 行到 5 行，但一般的想法是你想打印出誰越過終點線，但你只希望打印一次。
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