我正在編寫一個示例問候程序。我有一個隨機的問候消息列表，其中包含模板字符串作為名稱。我的代碼如下from random import randintrandom_greeting = [ "Hello {name}, Hope you are doing well", "Hello {name}, Hope you are having a great day", "Hello {name}, Nice to meet you" ]class Greetings(object): global random_greeting def read_input(self): return input("What is your name? ") def print_greeting_rand(self, name): greet_length = len(random_greeting) random_int = randint(0, greet_length-1) message = random_greeting[random_int] print(f"{message}") # Here {name} not coming into scopeif __name__ == "__main__": greet = Greetings() name = greet.read_input() greet.print_greeting_rand(name)所以 random_greeting 有名稱為模板字符串的消息列表{name}。print_greeting_rand在我基于隨機索引獲取問候消息并使用 Python F-Strings 打印的函數中，{name}沒有按預期進行解釋。有什么建議嗎？
3 回答
手掌心
TA貢獻1942條經驗 獲得超3個贊
您可以利用一個簡單的正則表達式和**kwargs：
import random, re
class Greetings(object):
greetings = [
"Hello {name}, Hope you are doing well {when}",
"Hello {name}, Hope you are having a great day",
"Hello {name}, Nice to meet you"
]
rx = re.compile(r'{([^{}]+)}')
vars = {}
def read_input(self):
return input("What is your name? ")
def print_greeting_rand(self, **kwargs):
self.vars = kwargs
tmpl = self.rx.sub(self.__replace__, random.choice(self.greetings))
print(tmpl)
def __replace__(self, m):
var = m.group(1)
if var in self.vars:
return self.vars[var]
return m.group(0)
if __name__ == "__main__":
greet = Greetings()
greet.print_greeting_rand(name=greet.read_input(), when="today")
解釋：
這將掃描字符串以查找形式為{+ variable_name +的任何變量}，并在在參數中找到它時替換它**kwargs。如果沒有找到，它就簡單地返回{variable_name}，即保持原樣。
請參閱regex101.com上的表達式演示。
ITMISS
TA貢獻1871條經驗 獲得超8個贊
不幸的是，對于 f-strings 你不能這樣做，因為它們會立即被評估，所以你可以做的是使用：
from random import choice
random_greeting = [
"Hello {name}, Hope you are doing well",
"Hello {name}, Hope you are having a great day",
"Hello {name}, Nice to meet you"
]
def print_greeting_rand(self, name):
message = choice(random_greeting)
print(message.format(name=name))
喵喵時光機
TA貢獻1846條經驗 獲得超7個贊
你要
print(message.format(name=name))
這同樣適用于 f 弦。
print(f'{message}'.format(name=name))添加回答
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