我編寫了以下代碼來理解多進程環境中的 sys.excepthook。我正在使用 python 3。我創建了 2 個進程，它們將打印并等待獲取 ctrl+c。from multiprocessing import Processimport multiprocessingimport sysfrom time import sleepclass foo:    def f(self, name):        try:            raise ValueError("test value error")        except ValueError as e:            print(e)        print('hello', name)        while True:            passdef myexcepthook(exctype, value, traceback):    print("Value: {}".format(value))    for p in multiprocessing.active_children():        p.terminate()def main(name):    a = foo()    a.f(name)sys.excepthook = myexcepthookif __name__ == '__main__':    for i in range(2):        p = Process(target=main, args=('bob', ))        p.start()當我按下時，我期待以下結果ctrl+Cpython /home/test/test.pytest value errorhello bobtest value errorhello bobValue: <KeyboardInterrupt>但不幸的是，我得到了以下結果。/home/test/venvPython3/bin/python /home/test/test.pytest value errorhello bobtest value errorhello bobError in atexit._run_exitfuncs:Traceback (most recent call last):Process Process-1:  File "/usr/lib/python3.6/multiprocessing/popen_fork.py", line 28, in poll    pid, sts = os.waitpid(self.pid, flag)KeyboardInterruptTraceback (most recent call last):  File "/usr/lib/python3.6/multiprocessing/process.py", line 258, in _bootstrap    self.run()  File "/usr/lib/python3.6/multiprocessing/process.py", line 93, in run    self._target(*self._args, **self._kwargs)  File "/home/test/test.py", line 26, in main    a.f(name)  File "/home/test/test.py", line 15, in f    passKeyboardInterruptProcess Process-2:Traceback (most recent call last):  File "/usr/lib/python3.6/multiprocessing/process.py", line 258, in _bootstrap    self.run()  File "/usr/lib/python3.6/multiprocessing/process.py", line 93, in run    self._target(*self._args, **self._kwargs)  File "/home/test/test.py", line 26, in main    a.f(name)  File "/home/test/test.py", line 15, in f    passKeyboardInterruptProcess finished with exit code 0如果有人能指出我做錯了什么，那將是一個很大的幫助。另外，請讓我知道如何獲得預期的輸出。