我正在嘗試解析一個 xml：附上 xml，因為這里太長了https://drive.google.com/file/d/1CPleC1gBAR6n7lcyiR_zVMEjkowo3gUU/view?usp=sharingtype L1CProduct struct { XMLName xml.Name `xml:"n1:Level-1C_User_Product"` N1GeneralInfo N1GeneralInfo `xml:"n1:General_Info"`}type N1GeneralInfo struct { XMLName xml.Name `xml:"n1:General_Info"` ProductInfo ProductInfo `xml:"Product_Info"` SpectralInformationList SpectralInformationList `xml:"Product_Image_Characteristic>Spectral_Information_List"`}type SpectralInformationList struct { XMLName xml.Name `xml:"Spectral_Information_List"` SpectralInformation []SpectralInformation `xml:"Spectral_Information"`}type SpectralInformation struct { XMLName xml.Name `xml:"Spectral_Information"` BandId string `xml:"bandId,attr"` PhysicalBand string `xml:"physicalBand,attr"`}type ProductInfo struct{ XMLName xml.Name `xml:"Product_Info"` ProductStartTime string `xml:"PRODUCT_START_TIME"` GenerationTime string `xml:"GENERATION_TIME"` ProductUri string `xml:"PRODUCT_URI"`}func parseXml() { // Open our xmlFile // xmlPath := inProcessPath + "/MTD_MSIL1C.xml" xmlPath := "/home/htc/Lizer/backend/InProcessResults/MTD_MSIL1C.xml" xmlFile, err := os.Open(xmlPath) // if we os.Open returns an error then handle it if err != nil { fmt.Println(err) } fmt.Println("Successfully Opened " + xmlPath) // defer the closing of our xmlFile so that we can parse it later on defer xmlFile.Close() // read our opened xmlFile as a byte array. byteValue, _ := ioutil.ReadAll(xmlFile) fmt.Printf("\nData: %s", byteValue) // we initialize our Users array var users L1CProduct // we unmarshal our byteArray which contains our // xmlFiles content into 'users' which we defined above xml.Unmarshal(byteValue, &users) fmt.Println(users.N1GeneralInfo.ProductInfo.ProductStartTime + "o") println(users.N1GeneralInfo.SpectralInformationList.SpectralInformation[1].BandId)}但是當文件被正確讀取時，mi xml 結構是空的它就像結構是空的：輸出：**
1 回答
犯罪嫌疑人X
TA貢獻2080條經驗 獲得超4個贊
如果你想要:xml 中的解析器
喜歡
xml:"n1:Level-1C_User_Product"
應該：
xml:"https://psd-14.sentinel2.eo.esa.int/PSD/User_Product_Level-1C.xsd Level-1C_User_Product"
請參閱：在 GO 中解析 Xml 以獲取標簽中帶有“：”的屬性
下面是一個演示：
package main
import (
"encoding/xml"
"fmt"
"os"
)
type L1CProduct struct {
XMLName xml.Name `xml:"https://psd-14.sentinel2.eo.esa.int/PSD/User_Product_Level-1C.xsd Level-1C_User_Product"`
N1GeneralInfo N1GeneralInfo
}
type N1GeneralInfo struct {
XMLName xml.Name `xml:"https://psd-14.sentinel2.eo.esa.int/PSD/User_Product_Level-1C.xsd General_Info"`
ProductInfo ProductInfo `xml:"Product_Info"`
}
type ProductInfo struct {
XMLName xml.Name `xml:"Product_Info"`
ProductStartTime string `xml:"PRODUCT_START_TIME"`
GenerationTime string `xml:"GENERATION_TIME"`
ProductUri string `xml:"PRODUCT_URI"`
}
func parseXml() {
// Open our xmlFile
// xmlPath := inProcessPath + "/MTD_MSIL1C.xml"
xmlPath := "./MTD_MSIL1C.xml"
// read our opened xmlFile as a byte array.
byteValue, _ := os.ReadFile(xmlPath)
// we initialize our Users array
var users L1CProduct
err := xml.Unmarshal(byteValue, &users)
if err != nil {
fmt.Printf("%v\n", err)
}
fmt.Println(users.N1GeneralInfo.ProductInfo.ProductStartTime + "o")
}
func main() {
parseXml()
}
以下是輸出：
2022-11-09T16:55:19.024Zo
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