該代碼未顯示任何錯誤。但是，我得到了意外的輸出。我應該得到最小的年齡數字，但我一直得到的是最后輸入的年齡值。你能幫我指出這段代碼中的錯誤嗎？也許getYoungestPet()方法中存在一些邏輯錯誤？package pet;public class Pet {    public static String petName;     public static int petAge, petWeight;    int youngestAge=9999;    static int test;    public static String setPetName()    {      return petName;    }    public int setPetAge()    {        return petAge;    }    public int setPetWeight()    {        return petWeight;    }    public int getYoungestPet() //probably an error here..?    {        if (petAge<youngestAge)            youngestAge=petAge;        return youngestAge;    }}package pet;import java.util.Scanner;public class PetMain extends Pet{    public static void main(String[] args)    {    System.out.println("How many pets do you want to enter? " );     Scanner data= new Scanner(System.in);    int petNumber=data.nextInt();    for (int i = 1;i<=petNumber; i++)    {    Pet PetObject = new Pet();     System.out.println("Please enter name for Pet " + i );       Scanner input = new Scanner(System.in);       petName= input.next();            System.out.println("Your pet's name is : " + petName);    System.out.println(" ");    System.out.println("Please enter " + petName + "'s Age" );       petAge= input.nextInt();        System.out.println("Your pet's age is : " + petAge);    System.out.println(" ");    System.out.println("Please enter " + petName + "'s Weight" );        petWeight= input.nextInt();    System.out.println("Your pet's weight is : " + petWeight);    System.out.println(" ");                        System.out.println(PetObject.getYoungestPet());    }}}該代碼應該顯示最小的年齡，但它顯示的是最新輸入的年齡。