from math import floor

def check_if_number_exists(number, digit_to_find):

    # check if the number is positive

    if number < 0:

        Number = -number

    else:

        Number = number

    while(Number != 0):

        # run loop for extracting each digit

        Digit = Number % 10 # gives the last number

        Number = floor(Number / 10) # removing the last digit

        if Digit == digit_to_find:

            print("the number contains " + str(digit_to_find) + ' in ' + str(number))

            break

#                      sequencenumber, number_to_check                    

check_if_number_exists(45638, 3)

還有另一種方法，您可以將數字轉換為字符串，然后檢查字符串的每個元素！