我已經為基本 SIR 模型繪制了一個圖。我對我的情節很滿意，但是，我希望能夠有一個交互式滑塊來調整我的參數 beta 和 gamma。我希望它們的范圍都在 0 到 1 之間，并且用戶能夠將它們遞增 0.01。有人可以幫我在我的代碼中實現這個嗎？感謝您提前抽出時間。這是我的代碼：# # Solving SIR Model in Python (INTERACTIVE)# \# Importing packages:# In[10]:# Display in LaTeX style.from sympy.interactive import printingprinting.init_printing(use_latex = True)# For integration.import scipy.integrate # For arrays (Python does not have native arrays).import numpy as np# For graphing.import matplotlib.pyplot as plt # Prevents the pop-up graphs in a separate window.get_ipython().run_line_magic('matplotlib', 'inline')# Allows for an interactive widget bar.from ipywidgets import interactive # \# Defining differential equations:# In[11]:def SIR_model(y, t, beta, gamma):    S, I, R = y        dS_dt = -beta*S*I    dI_dt = beta*S*I - gamma*I    dR_dt = gamma*I        return([dS_dt, dI_dt, dR_dt,])# \# Defining initial conditions:# In[12]:S0 = 0.95I0 = 0.05R0 = 0.0beta = 0.35gamma = 0.1# \# Defining time vector:# In[13]:# Graph from 0 to 100, include 10000 points.t = np.linspace(0, 100, 10000) # \# Defining solution:# In[14]:# Resultsolution = scipy.integrate.odeint(SIR_model, [S0, I0, R0], t, args=(beta, gamma))solution = np.array(solution)# \# Plotting the result:# In[20]:plt.figure(figsize=[8, 5])plt.plot(t, solution[:, 0], label="S(t)")plt.plot(t, solution[:, 1], label="I(t)")plt.plot(t, solution[:, 2], label="R(t)")plt.grid()plt.legend()plt.title("SIR Model")plt.xlabel("Time")plt.ylabel("Proportions of Populations")# THIS DOES NOT WORK !!!#interactive_plot = interactive(SIR_model, betta=(0.35,1,0.01), gamma=(0.1,1,0.01))#interactive_plotplt.show()這是輸出。