好吧，也許我找不到答案，因為我不確定如何表達，但我有一個名為 Info 的類和另一個名為 Packet 的類，它們都使用 boost 編譯成 Python 擴展，我想返回一個指向 Packet 模塊中的 Info 對象的指針。信息.cpp#include "info.h"Info::Info(int i_, int j_){    this->i = i_;    this->j = j_;} Info::~Info(){}BOOST_PYTHON_MODULE(Info){    class_<Info>("Info", init<int, int>())    .def_readwrite("i", &Info::i)    .def_readwrite("j", &Info::j);}數據包.cpp：Packet::Packet(int i_, int j_, PyObject* addr_, bool a_, bool b_){    this->i = i_;    this->j - j_;    this->addr = addr_;    this->a = a_;    this->b = b_;}// some other functionsInfo* Packet::test(){    return new Info(1,2);}BOOST_PYTHON_MODULE(Packet){    class_<Packet>("Packet", init<int, int, PyObject*, bool, bool>())        /*some other functions*/        .def("test", &Packet::test, return_value_policy<reference_existing_object>());}testPacket.py:from Packet import *# this works correctlyp = Packet(1,2, None, False, False)# this crashest = p.test()錯誤信息：Traceback (most recent call last):  File "/usr/lib64/python3.6/runpy.py", line 193, in _run_module_as_main    "__main__", mod_spec)  File "/usr/lib64/python3.6/runpy.py", line 85, in _run_code    exec(code, run_globals)  File "/tmp/lirui/testPacket.py", line 5, in <module>    print(p.test())TypeError: No Python class registered for C++ class Info有什么方法可以返回指向 Info 對象的指針嗎？