我正在開發一款井字游戲，該游戲的功能是將列表中的連字符替換為 X 和 O 以形成網格。我也是 python 的初學者，所以這段代碼會很笨重。問題是我希望游戲可以重新玩，但我找不到將列表重置為開始時使用的連字符的方法。這是一段簡化的代碼，可以更好地說明問題：list = ["-","-","-", "X","O"]def replace(): list[0] = list[3]def main(): replace() play_again = input ("play again?") if play_again == "yes": main() else: exit() main()這使得列表從["-","-","-", "X","O"]變為["X","-","-", "X","O"]，從而使游戲正常運行。我希望能夠做的是以某種方式回到list玩家["-","-","-", "X","O"]再次玩游戲的時候。不幸的是，該列表似乎停留在["X","-","-", "X","O"]. 我試過了：list = ["-","-","-", "X","O"]在上方添加replace()list[0] = "-"在上方添加replace()這些選項都不起作用。是否可以將 的值重置list為我開始時的值？如果是這樣，我應該如何處理這個問題？
1 回答
嚕嚕噠
TA貢獻1784條經驗 獲得超7個贊
使您的代碼“工作”的最簡單的更改是：
def main():
global list
list = ["-","-","-", "X","O"]
replace()
play_again = input ("play again?")
if play_again == "yes":
main()
else:
exit()
（雖然這不是我從頭開始做這件事的方式——但你已經指出笨重的代碼是可以的/預期的，所以我不打算在這里嘗試修復它。）
這也將起作用，并且不需要global聲明：
def main():
list[:] = ["-","-","-", "X","O"]
replace()
play_again = input ("play again?")
if play_again == "yes":
main()
else:
exit()
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