下面的代碼適用于 PySide,但不適用于 PySide2:當操作被觸發時 (Ctrl+S),函數saveResults被調用filename=False,而不是None我所期望的(和 PySide 的情況一樣:您可以通過切換 import 語句來測試)。我想知道行為是否發生了變化,或者我的代碼中有什么需要修復的?(我知道我可以使用 lambda 技巧,我更好奇是 Slot 語法還是需要精度的連接)。import sys# PySide2 won't pop up the QFileDialogfrom PySide2.QtGui import *from PySide2.QtWidgets import *from PySide2.QtCore import Slot# # PySide works fine:# from PySide.QtGui import *# from PySide.QtCore import Slotclass MyWindow(QMainWindow): def __init__(self): QMainWindow.__init__(self) self.fileMenu = self.menuBar().addMenu("&File") act = QAction("Save results...", self) act.triggered.connect(self.saveResults) # <--- should call saveResults(None) #act.triggered.connect(lambda: self.saveResults(None)) # fixes the issue act.setShortcuts([QKeySequence.Save]) self.fileMenu.addAction(act) @Slot() def saveResults(self, filename=None): print ('Calling saveResults, filename is', filename) if filename is None: (filename, selectedfilter) = QFileDialog.getSaveFileName(self,"Save results as ", ".", "NPY Files (*.npy);;Image files (*.png *.tif *.tiff *.bmp);;All files (*)") # ... exit if cancel clicked # finally save the file: print('Saving', filename)qt_app = QApplication(sys.argv)app = MyWindow()app.show()qt_app.exec_()
1 回答

寶慕林4294392
TA貢獻2021條經驗 獲得超8個贊
這似乎是一個錯誤,解決方法是通過關鍵字觸發連接:
# ...
self.fileMenu = self.menuBar().addMenu("&File")
act = QAction("Save results...", self, triggered=self.saveResults)
act.setShortcuts([QKeySequence.Save])
self.fileMenu.addAction(act)
# ...
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