有一個每秒創建文件的程序。我想將文件名附加到切片中并打印出來?，F在我的程序執行不正確，它附加名稱但僅用于一個文件名。所以我希望得到[]string{"1","2","3"}，而不是我得到[]string{"1","1","1"}，[]string{"2","2","2"}, []string{"3","3","3"}。如何更正我的程序以獲得預期結果？package mainimport ( "encoding/csv" "fmt" "os" "strconv" "time")func main() { for { time.Sleep(1 * time.Second) createFile() }}func createFile() { rowFile := time.Now().Second() fileName := strconv.Itoa(rowFile) file, err := os.OpenFile(fileName, os.O_CREATE|os.O_WRONLY|os.O_APPEND, 0644) if err != nil { fmt.Println(err) } defer file.Close() writer := csv.NewWriter(file) writer.Comma = '|' err = writer.Write([]string{""}) if err != nil { fmt.Println(err) } countFiles(fileName)}func countFiles(fileName string) { arrFiles := make([]string, 0, 3) for i := 0; i < 3; i++ { arrFiles = append(arrFiles, fileName) } fmt.Println(arrFiles)// here I expect ["1","2","3"] then ["4","5","6"] and so on. But now there is ["1","1","1"] then ["2","2","2"] and so on}
1 回答
FFIVE
TA貢獻1797條經驗 獲得超6個贊
createFile()不會以任何方式保留創建的文件名。你可以這樣做：
package main
import (
"encoding/csv"
"fmt"
"os"
"strconv"
"time"
)
func main() {
files := []string{}
for {
time.Sleep(1 * time.Second)
files = append(files, createFile())
fmt.Println(files)
}
}
func createFile() string {
rowFile := time.Now().Second()
fileName := strconv.Itoa(rowFile)
file, err := os.OpenFile(fileName, os.O_CREATE|os.O_WRONLY|os.O_APPEND, 0644)
if err != nil {
fmt.Println(err)
}
defer file.Close()
writer := csv.NewWriter(file)
writer.Comma = '|'
err = writer.Write([]string{""})
if err != nil {
fmt.Println(err)
}
return fileName
}
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